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lianna [129]
3 years ago
8

Multiply each equation by a number that producess opposite coefficients for x and y?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Let's solve your system by substitution.

3x−2y=−12;4x+5y=7

Step: Solve3x−2y=−12for x:

3x−2y=−12

3x−2y+2y=−12+2y(Add 2y to both sides)

<u>3x</u>=   <u>2y−12 </u>

3          3

=

<u>2y−12 </u>

3

(Divide both sides by 3)

x=

<u>2 </u>

3    y−4

Step: Substitute

<u>2 </u>

3

y−4 for x in 4x+5y=7:

4x+5y=7

4( 2/3  y−4)+5y=7

<u>23 </u>

3

y−16=7(Simplify both sides of the equation)

<u>23</u>

3

y−16+16=7+16(Add 16 to both sides)

<u>23</u>

3

y=23

<u>23</u>

3  y

<u>23 </u>

3      =  23<u> </u>

<u>23 </u>

3

(Divide both sides by 23/3)

y=3

Step: Substitute 3 for y in x=

<u>  2   </u>

3 y−4:

x=

<u>  2   </u>

3 y−4

x=  <u>  2   </u>

  3 (3)−4

x=−2(Simplify both sides of the equation)

Answer:

x=−2 and y=3                    (underlined and / are fractions or division)

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Nadya [2.5K]
They are vertical angles so you need to make the following equal

7y=5y+36 and 3x-21=2x+4

Solve for y and then x

7y=5y+36

Subtract 5y on both sides to get

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Then divide by 2 on both sides to Get y=18

For 3x-21=2x+4,

Subtract 2x on both sides to obtain

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Then add 21 to both sides to get

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4 0
3 years ago
Use mental math to solve the equation z/-12 = -5
Illusion [34]
Z=60

because
z/-12 = -5
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3 years ago
Find the area of a square with sides of length 3/4 inch.
Natali5045456 [20]

The area of the square is 9/16 sq.inches or 0.56 sq.inches

<u>Step-by-step explanation</u>:

<u>The formula used to find area of the square is :</u>

Area of the square = a².

where,

a is the length of the each side of the square.

It is given that, the length of the side of square is 3/4 inch.

Therefore, the value of a is 3/4.

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Ron and amber bought a pizza. Ron ate 3/10 of the pizza. Am bee ate 1/10 of the pizza together which fraction of the pizza did t
anzhelika [568]

Answer:

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Step-by-step explanation:

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Write each sum as a product of two factors Problem= 3x+(2+x)+5*2
ivanzaharov [21]
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