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lianna [129]
3 years ago
8

Multiply each equation by a number that producess opposite coefficients for x and y?

Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Let's solve your system by substitution.

3x−2y=−12;4x+5y=7

Step: Solve3x−2y=−12for x:

3x−2y=−12

3x−2y+2y=−12+2y(Add 2y to both sides)

<u>3x</u>=   <u>2y−12 </u>

3          3

=

<u>2y−12 </u>

3

(Divide both sides by 3)

x=

<u>2 </u>

3    y−4

Step: Substitute

<u>2 </u>

3

y−4 for x in 4x+5y=7:

4x+5y=7

4( 2/3  y−4)+5y=7

<u>23 </u>

3

y−16=7(Simplify both sides of the equation)

<u>23</u>

3

y−16+16=7+16(Add 16 to both sides)

<u>23</u>

3

y=23

<u>23</u>

3  y

<u>23 </u>

3      =  23<u> </u>

<u>23 </u>

3

(Divide both sides by 23/3)

y=3

Step: Substitute 3 for y in x=

<u>  2   </u>

3 y−4:

x=

<u>  2   </u>

3 y−4

x=  <u>  2   </u>

  3 (3)−4

x=−2(Simplify both sides of the equation)

Answer:

x=−2 and y=3                    (underlined and / are fractions or division)

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