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Makovka662 [10]
3 years ago
15

A compound x is an important ingredient of an antacid. It is also used in fine extinguishers. Identify x.

Chemistry
2 answers:
svlad2 [7]3 years ago
4 0

Answer:

NAHCO3

Explanation:

this is the answer from textbook

Maslowich3 years ago
3 0
NaHCO3 is the required substance often used in antacid and is used in Soda Acid Fire Extinguisher.
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Why are stars special sources of light?(2 points)
Alex787 [66]

Answer:

They give off their own light energy

Explanation:

I'm taking astronomy and I answered this questions not too long ago

8 0
2 years ago
Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)
Studentka2010 [4]

Answer:

Fluorine

Explanation:

Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell.

4 0
3 years ago
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Which element is present in all organic compounds?
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The anser is 1, carbon
5 0
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Calculate the moles of 36.030 g of H2O.
lions [1.4K]

Answer: 1.99 mol h20

Explanation:

you have 36.030 g, trying to get it into mols

to get from g to mols, use the molar mass (periodic table)

36.030 g h20 (1 mol/18.02g) = 1.99 mol h20

4 0
3 years ago
The standard internal energy change for a reaction can be symbolized as Δ U ∘ rxn or Δ E ∘ rxn . For each reaction equation, cal
rosijanka [135]

Answer : The internal energy change is, -506.3 kJ/mol

Explanation :

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -511.3kJ/mol=-511300.0J/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 0 - 2 = -2 mole

That means, value of \Delta n_gRT = 0

R = gas constant = 8.314 J/mol.K

T = temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-511300.0J/mol)-[-2mol\times 8.314J/mol.K\times 298K

\Delta U=-511300.0J/mol+4955.144J/mol

\Delta U=-506344.856J/mol=-506.3kJ/mol

Therefore, the internal energy change is -506.3 kJ/mol

6 0
3 years ago
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