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Alex73 [517]
3 years ago
14

Pl help it’s for homwork

Chemistry
1 answer:
aleksklad [387]3 years ago
3 0
A. surface tension
I hope this helps
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Which of the following compounds would have the lowest
OLga [1]
Nm3R is the correct answer
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3 years ago
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Match the element with its description. Match Term Definition Potassium A) Great conductor of heat and electricity Barium B) Mal
mezya [45]
<span>Barium - A) Great conductor of heat and electricity Potassium - B) Malleable and highly reactive Boron - C) Has properties of both metals and nonmetals Neon - D) Nonreactive gas Let's look at each element and it's place on the periodic chart to see what matches. Potassium - This is on the far left column for alkali metals. This means it's highly reactive and since it's a metal, it's both malleable and conductive. Looking at the available options, "B) Malleable and highly reactive" is the best choice. Barium - This element is in the second column from the left, so it's a fairly reactive metal, but not nearly as reactive as Potassium above. So "A) Great conductor of heat and electricity" is the best choice here, although I wouldn't call it "great". The resistivity of barium is about 20 times larger than copper. Boron - This element is about in the middle of the periodic chart, so it does have the properties of both metals and nonmetals. So "C) Has properties of both metals and nonmetals" is the best choice. Neon - This is in the far right column for noble gasses. Very non-reactive. So "D) Nonreactive gas" is the best choice.</span>
5 0
4 years ago
55.2 mL of 0.500 M potassium hydroxide is used to neutralize 27.4 mL of sulfuric
mr Goodwill [35]

Answer:

0.504 M

Explanation:

Step 1: Write the balanced neutralization reaction

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

Step 2: Calculate the reacting moles of KOH

55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:

0.0552 L × 0.500 mol/L = 0.0276 mol

Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol

Step 4: Calculate the concentration of H₂SO₄

0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:

[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M

6 0
3 years ago
HELP ASAP PLEASE!!!!
IRISSAK [1]

50 electron capacity

3 0
4 years ago
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How many atoms are in one molecule of Iron II sulfate
dezoksy [38]
Answer:
             The number of atoms contained by one molecule of Iron (II) Sulfate are 6.

Explanation:
                   Iron (II) Sulfate is mage up of two parts. One is the Positive part which constitutes of Fe⁺² and a negative part which constitutes of a polyatomic anion i.e. SO₄²⁻. As there are four Oxygen and one sulfur atom in sulfate Ion so sulfate ion contains 5 atoms in total. Therefore, five atoms from sulfate iona dn one atom of Iron ion makes a total of 6 atoms in one molecule of Iron (II) Sulfate.
5 0
3 years ago
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