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natima [27]
3 years ago
11

Find the value of x that makes the equation true 17 - 5(2x - 9) = -(-6x + 10) + 4​

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

17/4

Step-by-step explanation:

17−5(2x−9)=−(−6x+10)+4

17−5(2x−9)=−(−6x+10)+4

17+−10x+45=6x+−10+4

(−10x)+(17+45)=(6x)+(−10+4)

−10x+62=6x+−6

−10x+62=6x−6

−10x+62−6x=6x−6−6x

−16x+62=−6

−16x+62−62=−6−62

−16x=−68

-16x/16 = -68/16

x = 17/4

 

pogonyaev3 years ago
4 0

Answer:

i think x=4.75

Step-by-step explanation:

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The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
3 years ago
I'm so confused, know the answer?​
Vikki [24]

Answer:

P = -10

5p - 8(p + 1) > 16

5(-10) - 8(-10 + 1) > 16

-50 - 8(-9) > 16

-50 + 72 > 16

22 > 16

7 0
2 years ago
1.06 SINUSOIDAL GRAPHS VERTICAL SHIFT
Ket [755]

Answer:

I do not understand very well but they are already helping me

4 0
3 years ago
Homework due in 10 minutes!!!
Brut [27]
$3,456 will be given to the band.

Simply multiplying 57,600 and 6% which is 0.06, you get 3,456.
6 0
3 years ago
Read 2 more answers
Identify the 35th term of an arithmetic sequence where a1 = −7 and a18 = 95.
borishaifa [10]
Th term of an arithmetic sequence:

We have to find the difference (d)

an=a₁+(n-1)d

Data:
a₁=-7
a₁₈=95

95=-7+(18-1)d
95+7=17d
17d=102
d=102/17
d=6

Now, we can calculate the 35 th term of an arithmetic sequence:
a₃₅=-7+(35-1)*6
a₃₅=-7+34*6
a₃₅=-7+204
a₃₅=197

Answer: the 35th term of this arithmetic sequence is 197. (a₃₅=197)

4 0
3 years ago
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