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4 years ago

13

Find the value of x. please show your work

1 answer:

docker41 [41]4 years ago

4 0

Answer:x = 60

Step-by-step explanation:

The given triangle is an equilateral triangle. This is so because all the angles are equal. This also means that all the sides are equal.

The sum of the angles on a straight line is 180 degrees. Assuming each angle of the equilateral triangle is y degrees, it means that

y + 2x = 180

y = 180 - 2x

The sum of the angles in a triangle is 180 degrees. It means that

y + y + y = 3y = 180

This means that

3(180 - 2x) = 180

540 - 6x = 180

6x = 540 - 180 = 360

x = 360/60 = 60

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250 round to the nearest tenth is?

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250 is the answer I think

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2 years ago

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Find the slope and write the equation to it and explain.

nikitadnepr [17]

B is your correct answer

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3 years ago

I am in need of assistance.

Alex_Xolod [135]

Answer:

A. x = 6.08, x = -0.58

Step-by-step explanation:

$\displaystyle \frac{2x}{x-4}-\frac{2x-5}{x^2-10x+24}=\frac{-3}{x-6}$

1. Factor the denominator.

$\displaystyle \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

2. Multiply the leftmost fraction by (x-6)/(x-6) to get common denominators.

$\displaystyle \Big ( \frac{x-6}{x-6} \Big ) \frac{2x}{x-4}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

3. Simplify.

$\displaystyle \frac{2x^2-12x}{(x-4)(x-6)}-\frac{2x-5}{(x-6)(x-4)}=\frac{-3}{x-6}$

4. Combine like terms.

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6}$

5. Multiply the right side of the equation by (x-4)/(x-4).

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3}{x-6} \Big ( \frac{x-4}{x-4} \Big )$

6. Simplify.

$\displaystyle \frac{2x^2-14x+5}{(x-4)(x-6)}=\frac{-3x+12}{(x-6)(x-4)}$

7. "Cancel" out the denominators because they are equivalent.

$2x^2-14x+5=-3x+12$

8. Set the equation equal to 0.

$2x^2-11x-7=0$

Quadratic formula:

$\displaystyle x = \frac{-b\pm \sqrt{b^2-4ac} }{2a}$

9. Factor using the quadratic formula.

$\displaystyle x = \frac{-(-11)\pm \sqrt{(-11)^2-4(2)(-7)} }{2(2)}$

10. Multiply and simplify.

$\displaystyle x = \frac{11 \pm \sqrt{177} }{4}$

11. Plug this into your calculator and solve for x.

$x=6.07603367 \approx 6.08$
$x=-0.57603367 \approx -0.58$

The correct answer is A. x = 6.08, x = -0.58.

8 0

3 years ago

7. Given secθ = V10 and tanθ= 3, determine<br> the following<br> csc(90° -θ)

marin [14]

$\csc(90^{\circ}-\theta)\\\\=\sec \theta \\\\=\sqrt{10}$

5 0

2 years ago

The water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters). If

Alecsey [184]

Answer:

The resultant velocity is 12.21 m/s.

Step-by-step explanation:

We are given that the water from a fire hose follows a path described by y equals 2.0 plus 0.9 x minus 0.10 x squared (units are in meters).

Also, v Subscript x is constant at 10.0 m/s.

The water from a fire hose follows a path described by the following equation below;

$y=2.0 + 0.9x-0.10x^{2}$

The velocity of the $x$ component is constant at = $v_x=10.0 \text{ m/s}$

and the point at which resultant velocity has to be calculated is (9.0,2.0).

Let the velocity of x and y component be represented as;

$v_x=\frac{dx}{dt} \text{ and } v_y=\frac{dy}{dt}$

Now, differentiating the above equation with respect to t, we get;

$y=2.0 + 0.9x-0.10x^{2}$

$\frac{dy}{dt} =0 + 0.9\frac{dx}{dt} -(0.10\times 2)\frac{dx}{dt}$

$\frac{dy}{dt} = 0.9\frac{dx}{dt} -0.2\frac{dx}{dt}$

$v_y = 0.9v_x -0.2v_x$

$v_y = 0.7v_x$

Now, putting $v_x=10.0 \text{ m/s}$ in the above equation;

$v_y = 0.7 \times 10.0$ = 7 m/s

Now, the resultant velocity is given by = $v=\sqrt{v_x^{2}+v_y^{2} }$

$v=\sqrt{10^{2}+7^{2} }$

= $\sqrt{149}$ = 12.21 m/s

5 0

3 years ago