Question:
The options are;
A. The distances in the Olympic final were farther on average.
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
C. The distances in the Olympic final were all greater than the US qualifier distances
D. none of the above
Answer:
The correct option is;
A. The distances in the Olympic final were farther on average.
Step-by-step explanation:
From the options given, we have
A. The distances in the Olympic final were farther on average.
This is true as the sum of the 5 points divided by 5 is more in the Olympic final
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier
C. The distances in the Olympic final were all greater than the US qualifier distances
This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final
D. none of the above
We have seen a possible correct option in option A
B = 7/8(A-9)
first you must distribute
B = 7/8A -7 7/8
add over the -7 7/8
B + 7 7/8 = 7/8A
now divide both sides by 7/8
B+7 7/8
----------- = A
7/8
Answer:
Step-by-step explanation:
Alright all we need to know is to understand our brackets
So 3+{2×(8-4+6)}-5-{9+4-[3×(1-5)]}
3+20-5-9+4-3(1-5)
Step 2
3+20-5-9+4-3(1-5) Simplify
18-9+4-3(1-5)
Step 3
18-9+4-3(1-5)
13-3(1-5)
13-(-12) Here is the tricky part (We aren't going to subtract because the brackets multiply the equations
So,
13+12=25
Your answer is 25
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Answer:
49°
Step-by-step explanation:
Since the angle measures of QPR and RPS add up to 88 degrees, you can set up an equation to solve for x and then RPS.
5x+34+8x+15=88
13x+49=88
13x=39
x=3
RPS=5x+34=5(3)+34=15+34=49°
Hope this helps!
