All categories

2 years ago

Which value of x makes the inequality 2(8 – x) < 4 true? A. x = –16 B. x = –9 C. x = 4 D. x = 10

Mathematics

2 answers:

Alik [6]2 years ago

8 0

2(8 - x) < 4

Instead of testing each individual value of the inequality, let's solve it to determine which value makes it true.

Let's start by dividing both sides by 2.

2(8 - x)/2 < 4/2

8 - x < 2

Subtract both sides by 8

8 - x - 8 < 2 - 8

-x < -6

Multiply/Divide both sides by -1 (either one works)

[NOTE: Remember to reverse the inequality sign when dividing/multiplying by a negative number!]

x > 6

Thus, any x value that's greater than 6 will make the inequality true. That would be answer choice D. Happy studying~

myrzilka [38]2 years ago

6 0

Answer:

Step-by-step explanation:

If we plug in any negative number as x, the result will always be greater than 4, which rules out answers A and B

lets try plugging in 4 as x to test answer C:

2(8-4)

2(4)= 8

8 is greater than 4, therefore C is wrong.

Lets try 10 as X (answer D):

2(8-10)

2(-2)

-4

We know that -4 is less than 4, therefore it makes the inequality true! :)

You might be interested in

Please order a b and c from least to greatest

vagabundo [1.1K]

Answer:

Jsi18 8 7

Step-by-step explanation:

Ndjsiwiw

4 0

2 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

If y varies directly as the square of x and Y = -54 when x = 9, then Y = -1

GarryVolchara [31]

Answer: false

Step-by-step explanation:

i just took the quiz and made a 60 so pls don’t be like me and fail it ;-;

6 0

3 years ago

Examine the ordered pairs in this relation. (8,5), (-3,8), (11, -1), (10,-5), (4,4) Which numbers are input values of the relati

slavikrds [6]

Answer:

{-3, 4, 8, 10, 11}

Step-by-step explanation:

The ordered pairs are usually defined as (input, output). That is, the input values of the relation are all of the first-numbers of the pairs:

{8, -3, 11, 10, 4}

We usually like to list members of a set in numerical order:

{-3, 4, 8, 10, 11} . . . . input values of the relation

3 0

2 years ago

The county fair charges $.50 per ride and $10 to get

Allisa [31]

Answer:

r=44 rides

Step-by-step explanation:

(32-10) ÷ 0.50 = r

r=44

6 0

2 years ago

Read 2 more answers