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2 years ago

Katy is walking toward a bridge. See full question below

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

No c

as she was initially 300m away from the bridge (distance from bridge=300m) (time=0) so it was her starting point.

and after 6 minutes (time=6min) she reached the bridge. (distance from bridge = 0m)

maks197457 [2]2 years ago

3 0

Answer:

C.Katy was initially 300 meters away from the bridge and it tooke her 6 minutes to reach the bridge.

Step-by-step explanation:

As you can see in the table when Katy had been walking for 0 minutes, she was 300 meters away, so initially Katy was 300 meters from the bridge.

When she reaches the bridge is when the distance is reduced to 0, since distances is reduced to 0 at 6 minutes, we can infer that it took her 6 minutes to reach the bridge, and that se was walking at a pace of 50 meters per minute.

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Step-by-step explanation:

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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

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<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

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$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

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3 years ago

Consider the function: f(x) = 2x^2 - 1.5x - 5 and its graph.

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Answer:

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Step-by-step explanation:

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$y=f(x-2) = 2(x-2)^2 - 1.5(x-2) - 5\\y = 2(x^2-4x+4) - 1.5x+3 - 5\\y=2x^2-8x+8-1.5x+3-5\\y=2x^2-9.5x+6$

f(x) = 2x² - 9.5x + 6

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Answer:

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Step-by-step explanation:

In the question some data is missing so, its correct question can be defined as follows:

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In Stage 4: It is right because it multiplies the variable on one of the two sides by -1. So, k=-7 to get.

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