The decimal form of 2/4 is..... 0.5
Thee function is given as:
<span>v(t)=t^2−2tv(t)=t^2−2t
</span>(a) What is the initial velocity?
Base from the function, the initial velocity would be zero.
(b) When does the object have a velocity of zero?
It would be during time zero. Also, at a time equal to two.
Answer:
L(t) = 5·sin(πt) +7
Step-by-step explanation:
The middle of the oscillation of the given function occurs when t=0. At that point, ...
L(0) = d = 7
The next maximum of the oscillation occurs when the argument of the sine function is π/2.
b·t = π/2
b = π/(2t) = π/(2·0.5) = π
At that maximum, the length is 12, so we have ...
L(0.5) = a·sin(0.5π) +7 = 12
a = 5
The function L(t) is ...
L(t) = 5·sin(πt) +7
Answer:
option D.
Step-by-step explanation:
let's take any point on the graph. let's say (2, 16)
and one point we know is (0, 0)
= 16($) / 2 (hrs)
= 8 $/ hrs
that is option D.
