If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)
Full question:
Linear Functions: Taking a Taxi
You take a trip to downtown Boston to walk the Freedom Trail with your family. After you walk through the Bunker Hill Memorial, your family decides to take a taxi to a restaurant for dinner. After 1 mile, the meter on the taxi says $4.75. It will cost $8.25 to go 3 miles. The cost varies linearly with the distance that you traveled. If you have $11 in your pocket, will you be able to take the cab 5 miles?
Answer:
Cannot go 5 miles having just $11
Step-by-step explanation:
Since the cost varies linearly with the distance that you traveled, to model the linear function for this problem we know that
1 mile = $4.75
And so to go x miles, we require $4.75x
Equation can therefore be modelled thus :
y=4.5x
Where y = total cost of transport in dollars
x= cost in dollars per mile
To find out if we can go 5 miles just having $11, we plug in 5 miles for x into the equation to find total cost of transport going 5 miles
y=4.5*5
y= $22.5
Therefore we cannot go 5 miles just having $11
Y = (3/4)x - 3
Use two of the ordered points to find the slope.
Then use the slope and one of the ordered pairs to find the y-intercept.
Pythagorean theorem.
a^2+b^2=c^2
6^2+7^2=c^2
36 + 49 = c^2
85 = c^2
sqrt of 85 = 9.22
So the best answer would be C. 9
