(x+3)^2 when tking the square root of both sides of this equation how many solutions will it have

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

0 solutions

Step-by-step explanation:

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Sangeet got 96% of his answers right in a test of 50 marks. What was his score out of 50?

Ulleksa [173]

Answer:

48 out of 50 correct answers

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2 years ago

The probability of winning a certain lottery is 1/77076 for people who play 908 times find the mean number of wins

Alex73 [517]

The mean is 0.0118 approximately. So option C is correct

<h3><u>Solution:</u></h3>

Given that , The probability of winning a certain lottery is $\frac{1}{77076}$ for people who play 908 times

We have to find the mean number of wins

$\text { The probability of winning a lottery }=\frac{1}{77076}$

Assume that a procedure yields a binomial distribution with a trial repeated n times.

Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.

$n=908, \text { probability } \mathrm{p}=\frac{1}{77076}$

$\text { Then, binomial mean }=n \times p$

$\begin{array}{l}{\mu=908 \times \frac{1}{77076}} \\\\ {\mu=\frac{908}{77076}} \\\\ {\mu=0.01178}\end{array}$

Hence, the mean is 0.0118 approximately. So option C is correct.

4 0

3 years ago

3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3

ozzi

Answer:

<h2>3. Infinitely many</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\(1)\\\text{if}\ a=d,\ b=e,\ c=f,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=5\end{array}\right\\(2)\\\text{if}\ a=d,\ b=e,\ c\neq f,\ \text{then the system of equations has no solution}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=-5\end{array}\right$

$(3)\\\text{if}\ a\neq d\ \text{or}\ b\neq e,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}x-3y=5\\2x-3y=5\end{array}\right$

$\text{We have:}\\\\\left\{\begin{array}{ccc}2x=-10y+6&\text{add 10y to both sides}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}2x+10y=6&\text{divide both sides by 2}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}x+5y=3\\x+5y=3\end{array}\right$