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timurjin [86]
3 years ago
6

Please answer this correctly

Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

63.59

Step-by-step explanation:

If the perimeter is 32.13, that means it is equal to

2r + 2πr/4 = 32.13

Solving this for r we get 9

Now, we can find the area, which is 3.14*r^2 / 4. Assuming pi to be 3.14 again, we get 63.585. Rounding this to the nearest hundredth, we get 63.59

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3 years ago
I need help with this please
Alexus [3.1K]

Answer:32

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
25:
MAVERICK [17]

Answer:

Pepe weighs 4600 grams.

Step-by-step explanation:

5.4 kilograms converted into grams is 5400 grams. Since Pepe is 800 grams lighter it would be 5400 - 800 which equals 4600 grams.

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Hope this helps!!

Have an awesome day!!

5 0
2 years ago
In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus 11 - 1 = 10.

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

  • The area to the left of the lower end of the interval shall be 1/2 \cdot (1 - 0.90)= 0.05.
  • The area to the left of the upper end of the interval shall be 0.05 + 0.90 = 0.95.

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

  • a degree of freedom of 10, and
  • a cumulative probability of 0.95.

t \approx 1.812.

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}},

where

  • t is the t-score at the upper end of the interval,
  • s_{n-1} is the unbiased estimate for the standard deviation, and
  • n is the sample size.

For this confidence interval:

  • t \approx 1.812,
  • s_{n-1} = 14, and
  • n = 11.

Hence the width of the 90% confidence interval is

\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65.

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

(38.3, 53.7).

5 0
3 years ago
Please help and explain why!!!!! Will mark as brainliest if correct!
Novosadov [1.4K]
Im sorry buuuuuuuuuut um thats too small maybe zoom in.. ;/
5 0
3 years ago
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