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kodGreya [7K]
3 years ago
9

22. One kilometer is approximately 0.62 mile. What fraction represents this length?

Mathematics
1 answer:
bixtya [17]3 years ago
6 0

<u><em>Answer:</em></u>

One kilometer is \frac{31}{50} miles

<u><em>Explanation:</em></u>

<u>To convert a decimal to a fraction:</u>

1- Write the decimal as a fraction whose denominator is 1

2- Multiply both numerator and denominator by multiples of 10 to eliminate the decimal point

3- Simplify the fraction you have

<u>Now, for the given problem:</u>

<u>The given decimal is 0.62, following the above steps:</u>

<u>Step 1: </u>

0.62 = \frac{0.62}{1}

<u>Step 2:</u>

We have two digits after the decimal point, so to eliminate the decimal point, we will multiply the numerator and the denominator by 100

0.62 = \frac{0.62}{1} * \frac{100}{100} = \frac{62}{100}

<u>Step 3:</u>

We can note that, in the fraction obtained from step 2, both the numerator and the denominator are divisible by 2, so we simplify as follows:

\frac{62}{100} = \frac{62/2}{100/2} =\frac{31}{50}

Hope this helps :)

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Answer:

TSA=6a²

TSA=6*17*17=1734 mm²

Step-by-step explanation:

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3 years ago
What is the answer to the following equation?<br>-x • 3x=?
Darina [25.2K]
The answer is -3 because:
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8 0
4 years ago
Bella earned the federal minimum wage in the year 2008. During that time, she worked 37.5 hours per week. How much money did she
Mariana [72]

Answer:

Belle's weekly earnings per week in 2008: $245.7

Step-by-step explanation:

The federal minimum wage in the year 2008 was: $6.55

She worked 37.5 hours per week.

She earn each week:

weekly earnings = 6.55*37.5=245.7

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3 years ago
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Pic attached for further detail
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3 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
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