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Anton [14]
3 years ago
10

Algebra 2

Mathematics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

Complex numbers are the one having two parts:

  • Real part
  • Imaginary part

Each of the part is simplified to (a+ib) format.

I hope it will help you.

Step-by-step explanation:

All parts are solved below:

Part 1:

=(-8i) + (41)+(-3 - 7i)

opening brackets

=-8i+41-3-7i

Adding like terms, real to real and imaginary to imaginary

= 38-15i

Part 2:

= (7 + 5i) - (7 - i)

Negative sign before bracket will change the signs to opposite

=7+5i - 7+ i

Adding like terms, real to real and imaginary to imaginary

=0 + 6i

Part 3:

=(8 – 4i) - (5 – 4i)

Negative sign before bracket will change the signs to opposite

= 8-4i-5+4i

Adding like terms, real to real and imaginary to imaginary

=3+0i

Part 4:

=(-8 - 4i) - (8 + i)

Negative signs before bracket will change the signs to opposite

=-8-4i-8-i

Adding like terms, real to real and imaginary to imaginary

=-16-5i

Part 5:

=(-3 - i) + (7 + 2i)

=-3-i+7+2i

Adding like terms, real to real and imaginary to imaginary

=4+1i

Part 6:

=-2 +6-(-4 + 2i)

Negative sign before bracket will change the signs to opposite

=-2+6+4-2i

Adding like terms, real to real and imaginary to imaginary

=8-2i

Part 7:

=(3 - 8i)(-4 + 4i)

Multiplying both bracket we get:

=-12+12i+32i+32i^2

By putting   i^2 = (-1)  

=12 +44i + 32 (-1)

Adding like terms, real to real and imaginary to imaginary

= -20+44i

Part 8:

=(5 – 3i)(-7 - 2i)

Multiplying both bracket we get:

=-35-10i+21i+6i^2

=-31+11i + 6 (-1)   (By putting   i^2 = (-1))

Adding like terms, real to real and imaginary to imaginary

=-37+11i

Part 9:

=8 + 8i

Part 10:

=(7 - 5i)(-4 + 3i)

Multiplying both bracket we get:

=-28+21i+20i-15i^2        (By putting   i^2 = (-1))

=-28+41i- 15(-1)

Adding like terms, real to real and imaginary to imaginary

=-13+41i

Part 11:

=7 + 4i

Part 12:

=(8 - 7i)(3 - 3i)

Multiplying both bracket we get:

=24-24i-21i+21i^2

=24-45i+21(-1)            (By putting   i^2 = (-1))

Adding like terms, real to real and imaginary to imaginary

=3-45i

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Let f(x) = -2x + 7 and g(x) = -6x + 3. Find fxg and state its domain.
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Option D: (f\times g)(x)=12 x^{2}-48 x+21; all real numbers.

Explanation:

Given that the functions are f(x)=-2 x+7 and g(x)=-6 x+3

We need to determine the value of (f\times g)(x) and its domain.

<u>The value of </u>(f\times g)(x)<u>:</u>

The value of (f\times g)(x) can be determined by multiplying the two functions.

Thus, we have,

(f\times g)(x)=f(x)\times g(x)

                =(-2x+7)(-6x+3)

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(f\times g)(x)=12 x^{2}-48 x+21

Thus, the value of (f\times g)(x) is (f\times g)(x)=12 x^{2}-48 x+21

<u>Domain:</u>

We need to determine the domain of the function (f\times g)(x)

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Thus, the function (f\times g)(x)=12 x^{2}-48 x+21 has no undefined constraints, the function is well defined for all real numbers.

Hence, Option D is the correct answer.

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