Answer:
5 hours
Step-by-step explanation:
Lillian is deciding between two parking garages.
Let the time required to park be represented by t
A = Amount
From Garage A
A = the amount Garage A would charge if Lillian parks for t hours
B = the amount Garage B would charge if Lillian parks for t hours.
Garage A
Garage A charges an initial fee of $4 to park plus $3 per hour.
A = $4 + $3 × t
A = 4 + 3t
Garage B charges an initial fee of $9 to park plus $2 per hour.
B = $9 + $2 × t
B = 9 + 2t
The hours parked, t, that would make the cost of each garage the same is calculated by equating A to B
A = B
4 + 3t = 9 + 2t
Collect like terms
3t - 2t = 9 - 4
t = 5 hours
Therefore, the hours parked, t, that would make the cost of each garage the same is 5 hours
Answer:
y=3x+(-3)
Step-by-step explanation:
y=mx+c
3=3(2)+c
3=6+c
c=-3
5m + 7/2 = -2m + 5/2
5m + 2m = 5/2 - 7/2
7m = -1
m = -1/7 <==
each friend would get 4 grapes, there will be some loftover at the end
Answer:
Number of jars can be filled from 15kg of the salt = 468 or 469 jars (Approx.)
Step-by-step explanation:
Given:
Amount of salt containing in jar = 32 gram
Total amount of salt in jar = 15 kg
Find:
Number of jars can be filled from 15kg of the salt
Computation:
Total amount of salt in jar = 15 kg
Total amount of salt in jar (in grams) = 15 x 1000 g
Total amount of salt in jar (in grams) = 15,000 g
Number of jars can be filled from 15kg of the salt = Total amount of salt in jar (in grams) / Amount of salt containing in jar
Number of jars can be filled from 15kg of the salt = 15,000 / 32
Number of jars can be filled from 15kg of the salt = 468.75
Number of jars can be filled from 15kg of the salt = 468 or 469 jars (Approx.)
