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2 years ago

AB was dilated by scale factor of 2 to create A'B',

Mathematics

2 answers:

stira [4]2 years ago

8 0

Answer:

The correct answer is answer choice (B.), M

Tpy6a [65]2 years ago

3 0

Answer:

Step-by-step explanation:

AB was dilated by scale factor of 2 to create A'B'.

Connect points A and A' with a straight line, connect points B and B' with a straight line. The point where these two straight lines will intersect is the center of dilation.

As you can see, these lines intersect at point M, so, point M is the center of dilation.

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3 years ago

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Answer:

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Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

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Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

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