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Blizzard [7]
2 years ago
12

each student desk holds 6 textbooks. if there are 12 desks in a room. How many textbooks can they hold altogether.

Mathematics
1 answer:
kogti [31]2 years ago
8 0

Answer:

72

Step-by-step explanation:

just times 6 by 12 to get the answer

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I’ll mark you brainlist show work
masya89 [10]

Answer:

whats a slope?

Step-by-step explanation:

3 0
3 years ago
Clara writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a
zheka24 [161]

Answer:

  CPCTC

Step-by-step explanation:

Statements 3 and 4 show the top and bottom triangles are congruent, and the left and right triangles are congruent. Statement 5 is making use of these facts to claim that the alternate interior angles are congruent. This claim is valid because ...

  Corresponding Parts of Congruent Triangles are Congruent (CPCTC)

7 0
3 years ago
Find the mean and the MAD. [Note: Type your answers as decimal numbers, rounded to the nearest tenth.] 135, 160, 145, 155, 170,
VashaNatasha [74]

Answer:

Mean = 151

MAD = 9.14

Step-by-step explanation:

Given the data:

135, 160, 145, 155, 170, 150, 142

Mean = Σx / n

Mean = 1057 / 7

Mean = 151

Mean absolute DEVIATION (MAD) : Σ(x - μ) / n

[(135-151) + (160-151) + (145-151) + (155-151) + (170-151) + (150-151) + (142-151)] / 7

Mean absolute deviation = 9.14

4 0
2 years ago
For a group of 100 people, compute(a) the expected number of days of the year that are birthdays of exactly 3 people.(b) the exp
Scilla [17]

Answer:

Step-by-step explanation:

Leaving leap years, a year contains 365 days.

For a group of 100 people, each person is independent of the other and probability of any day being his birthday has a chance of

\frac{1}{365}

a) Probability that  exactly 3 people have same birthday = \frac{1}{365^3}

Each day is independent of the other

And hence no of days having exactly 3 persons birthday out of 100 persons is binomial with n = 365 and p = \frac{1}{365^3}

Expected value of days = np = \frac{1}{365^2}

b) Distinct birthdays is binomail with p =1/365 and n = 365

Hence

expected value = np =1

4 0
3 years ago
Given ∆QRS≅∆TUV, QS=4v+3, and TV=7v-9, find the length of QS and TV.?
Anon25 [30]
If we are supposed to assume that QS=TV

4v+3=7v-9
minus 4v both sides
3=3v-9
add 9
12=3v
divide 3
4=v
v=4

sub back

4v+3=QS=TV
4(4)+3=QS=TV
16+3=QS
19=QS=TV

then answer is C
7 0
3 years ago
Read 2 more answers
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