each student desk holds 6 textbooks. if there are 12 desks in a room. How many textbooks can they hold altogether.

Please help . Really need done . Thank you . Will mark Brainly .

Gekata [30.6K]

Answer:

(5,2)

Step-by-step explanation:

Answer (5,2)

N(2)

W E(5)

S

8 0

2 years ago

For your fundraiser, you decide to hold a bake sale. In order to make bakery items, you had to purchase 12 pounds of sugar and 1

madam [21]

The question seems to be pointing towards a multiple choice response but I will do my best. The first equation would be 15x+12y=9.30 and the second would be 10x+4y=4.60, x represents flour and y represents sugar.

Hope this helps.

3 0

3 years ago

Find the two square roots of each complex number by creating and solving polynomial equations.

son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3 + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

$\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))$

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad

w₁= $\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))$ =4-i

w₂= $\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))$ =-1+i

2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad

w₁= $\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))$ = 3 - i

w₂= $\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))$ = -3 + i

3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad

w₁= $\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))$ = 1 + 2i

w₂= $\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))$ = -1 - 2i

4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad

w₁= $\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))$ = 2- 3i

w₂= $\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))$ = -2 + 3i

5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad

w₁= $\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))$ = 5 - 2i

w₂= $\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))$ = -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁= $\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))$ = 5 - 3i

w₂= $\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))$ = -5 + 3i

6 0

3 years ago

Kyle held a balloon 8 feet off the ground, straight above his head. Ava is standing 15 feet directly to the right of Kyle.

Mazyrski [523]

Complete Question:

Kyle held a balloon 8 feet off the ground, straight above his head. Ava is standing 15 feet directly to the right of Kyle.

Write an equation using the Pythagorean Theorem to find the value of x.

How far are Ava's feet from the balloon?

Answer:

Ava's feet is 17ft away from the balloon

Step-by-step explanation:

Given

$height = 8ft$

$distance = 15ft$

The attached image represents the scenario

Using Pythagoras theorem (from the attachment), we have:

$x^2 = 8^2 + 15^2$

$x^2 = 64 + 225$

$x^2 =289$

Take square roots of both sides

$x = \sqrt{289$

$x = 17$

6 0

3 years ago

Find the value of x for which 2x ^(1/ 2) = 32.

Mrac [35]

Answer:

The value of x will be 8

Step-by-step explanation:

We have given that $2\sqrt{x}=32$

We have to find the value of x

As $2\sqrt{x}=32$

For finding the value of x we have to square both side

On squaring both side

We done squaring both side for easy simplification

$4x=32$

So x = 8

So the value of x will be 8

So answer will be 8

5 0

3 years ago