When we factorise an expression, we are looking for simple factors that multiply to get the original expression. Usually it is very natural to factorise something like a quadratic in x. For example:
x^2 + 3x + 2 = (x+1)(x+2)
But there are other situations where factorisation can be applied. Take this quadratic:
x^2 - 9x = x(x-9)
This second example is closer to the question in hand. Just like x was a common factor to both x^2 and -9x, we are looking for a common factor to both 6b and 24bc. The common factor is 6b.
Hence 6b + 24bc = 6b(1 + 4c).
I hope this helps you :)
112 is that all multiplied and divided by three.
Answer:
Perimeter of shape,which is a convex polygon i.e quadrilateral = 24.2 in
Sides are 8.3 in, 8.3 in, 3.8 in ,and length of fourth side be x in.
As , Perimeter = Sum of all sides
→ 24.2 = 8.3 + 8.3 + 3.8 + x
→ 24.2 = 16.6 +3.8 + x
→ 24.2 = 20 .4 + x
Keeping like terms on one side, of equation
→ 24.2 - 20.4 = x
→ 3.8 = x
→ x = 3.8
So, length of fourth side = 3.8 in
The given shape is definately either a Parallelogram or a kite.
The cost of the monthly fee is 50$.. if the joining fee is 100.. take 200 and subtract that fee since it is included in the total. You’re left with 100. Note, the 200 is calculated for a 2 month period, so split the remaining 100 ,from the total 200, into 2. You’re left with 50 each month.
T=(C-100)/2 (T being 1 month) (C being the total cost/200)
Hopefully
Answer:
Step-by-step explanation:
(ab + bc)(ab + bc)
Simplifying
(ab + bc)(ab + bc)
Multiply (ab + bc) * (ab + bc)
(ab(ab + bc) + bc(ab + bc))
((ab * ab + bc * ab) + bc(ab + bc))
Reorder the terms:
((ab2c + a2b2) + bc(ab + bc))
((ab2c + a2b2) + bc(ab + bc))
(ab2c + a2b2 + (ab * bc + bc * bc))
(ab2c + a2b2 + (ab2c + b2c2))
Reorder the terms:
(ab2c + ab2c + a2b2 + b2c2)
Combine like terms: ab2c + ab2c = 2ab2c
(2ab2c + a2b2 + b2c2)
