The answer is x bc when you decreasing the interval f(x) it will equal (-2)
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Answer:
w is the width
L is the length
p is the perimeter
w=9
L=27
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Step-by-step explanation:
p=2[(L-4) + (w+1)]
⇔p=2[(3w-4) + (w+1)]
⇔p=2[4w-3]
⇔p=8w-6
⇔66=8w-6
⇔8w=72
⇔w=9
Then L=3w=27
:)
Answer:
The ones that can be used are (B and A)
The ones that cannot be used are (C and D)
Step-by-step explanation:
Because the panthers got 6 less and the tigers got 22…
b+6 would make 22 (panthers plus 6 makes tigers)
22-b would also be 6 because 6+b makes 22, so subtracting b from 22 makes 6
In order to find the smallest amount of cardboard needed, you need to find the total surface area of the rectangular prism.
Therefore, you need to understand how the cans are positioned in order to find the dimensions of the boxes: two layers of cans mean that the height is
h = 2 · 5 = 10 in
The other two dimensions depend on how many rows of how many cans you decide to place, the possibilities are 1×12, 2×6, 3×4, 4×3, 6×2, 12×1.
The smallest box possible will be the one in which the cans are placed 3×4 (or 4×3), therefore the dimensions will be:
a = 3 · 3 = 9in
b = 3 <span>· 4 = 12in
Now, you can calculate the total surface area:
A = 2</span>·(a·b + a·h + b·h)
= 2·(9·12 + 9·10 + 12·10)
= 2·(108 + 90 + 120)
= 2·318
= 636in²
Hence, the smallest amount of carboard needed for the boxes is 636 square inches.
