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3 years ago

Which of the following describes the “p/2” in the expression above?

Mathematics

1 answer:

julia-pushkina [17]3 years ago

5 0

Option B. Quotient is the right answer

Step-by-step explanation:

Given expression is:

p/2 +4(7+p)

Let us look at the options one by one

<u>A. factor</u>

p/2 is not a factor as the factor is always multiplied with another factor

<u>B. quotient</u>

This is the right answer as p is being divided by 2. The quotient of both will be used for further calculations

Hence,

Option B. Quotient is the right answer

Keywords: MCQs, Expressions

Learn more about polynomial expressions at:

#LearnwithBrainly

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Lulu wants to get fit. She started with 50 laps a day and she intends to add 10 laps every week. Write a mathematical expression

vlabodo [156]

Answer: 10x + 50

Step-by-step explanation:

lets say that x is equal to the amount of weeks that she runs. She starts off the first week with 50

Then, since she is adding 10 every week, you would do 10x, or 10 times the amount of weeks that she runs.

Since you originally started with 50, you have to add the 50 to the 10x.

So you get...

For example

on week 2, if you plug in 2 to x you get

10(2) +50

20 + 50

70 laps after the second week

7 0

1 year ago

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

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Area of triangle

$\\ \\$

We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

$\\ \\$

So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

$\\ \\$

$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

$\\ \\$

$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]