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Sonbull [250]
3 years ago
5

Why does the multiplication property of equality not allow us to divide both sides of an equation by zero?​

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

First of all, recall that division by zero is undefined; it's nonsensical; it's just not allowed.So zero certainly needs to be excluded when dividing.

But what about multiplying by zero?

The problem is that multiplying by zero can change the truth of an equation:

It can take a false equation to a true equation.

To see this, consider the false equation ‘

2 = 3

Multiplying both sides by zero results in the new equation

2 ⋅ 0 = 3 ⋅0 (that is, ‘0 = 0’), which is true.

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Is 8.001 bigger than 8.002​
son4ous [18]

Answer:

False

Step-by-step explanation:

8.001 is not greater than 8.002

4 0
3 years ago
Read 2 more answers
The lines passing through points (1, 1), (2, 3) and (3, 7), (2,5) on a grid would be ___<br> lines.
Harman [31]

Answer:

Step-by-step explanation:

can u be more specific on what your asking for please

5 0
3 years ago
Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
Express sin UU as a fraction in simplest terms.
alukav5142 [94]

The expression of sinU as a fraction is 12/13

Find the diagram attached.

To get the fraction represented by sinU, we will use the SOH CA TOA identity.

From the diagram;

  • Hypotenuse = SU = 13
  • Opposite = ST = 12 (angle opposite to m<U)

Since sin theta = opp/hyp

SinU = ST/SU

SinU = 12/13

Hence the expression of sinU as a fraction is 12/13

Learn  more on SOH CAH TOA here: brainly.com/question/20734777

5 0
3 years ago
Part B: Solve 2a − 5d = 30 for d. Show your work. (6 points)
stich3 [128]
<span>Given Equation: 2a − 5d = 30 

Solution:

2a - 5d = 30

-5d = 30 -2a

d = ( 30 - 2a )/ (-5)

  =  -6 + (2a/5) 

  = (2a/5) - 6

I hope this helps</span>
3 0
4 years ago
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