Need answers asap plz with work included (20 points)

7. Factor the expression.<br> 42 - 64

Dmitriy789 [7]

Answer:

-22 = -2^1×11^1

Step-by-step explanation:

Factor the following integer:

-22

Hint: | Is 22 divisible by 2?

The last digit of 22 is 2, which means it is even. Therefore 22 is divisible by 2:

22 = 2 11:

-22 = -2×11

Hint: | Now try to factor 11. Is 11 divisible by 2?

11 is not divisible by 2 since 11 is odd and 2 is even:

-22 = -2×11 (11 is not divisible by 2)

Hint: | Is 11 divisible by 3?

The sum of the digits of 11 is 1 + 1 = 2, which is not divisible by 3. This means 11 is not divisible by 3:

-22 = -2×11 (11 is not divisible by 2 or 3)

Hint: | Is 11 divisible by 5?

The last digit of 11 is not 5 or 0, which means 11 is not divisible by 5:

-22 = -2×11 (11 is not divisible by 2, 3 or 5)

Hint: | Is 11 divisible by 7?

Divide 7 into 11:

| | 1 | (quotient)

7 | 1 | 1 |

- | | 7 |

| | 4 | (remainder)

11 is not divisible by 7:

-22 = -2×11 (11 is not divisible by 2, 3, 5 or 7)

Hint: | Is 11 prime?

No primes less than 11 divide into it. Therefore 11 is prime:

-22 = -2×11

Hint: | Express -22 as a product of prime powers.

There is 1 copy of 2 and 1 copy of 11 in the product:

Answer: -22 = -2^1×11^1

3 0

2 years ago

What does it mean to eliminate a variable?

uranmaximum [27]

Answer:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.

So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.

7 0

2 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

3 years ago

Find the distance between the points (-9,2) and (-1,4). Round to the nearest tenth if necessary.

AlekseyPX

Answer:

The answer to the nearest tenth is 8.2

Step-by-step explanation:

In order to find the distance between any two points, you must use the distance formula. when you plug in the points into the formula you end up with 8.246, rounded to the nearest tenth would be 8.2. I hope this helps!

8 0

3 years ago

Please help :) thank you!

Jobisdone [24]

Answer:

800

Step-by-step explanation:

16 x 10 x 5= 800

5 0

2 years ago

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