1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
3 years ago
9

23% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and as

k each to name the reason he or she uses credit cards. Find the probability that the number of college students who say they use credit cards because of the rewards program is (a) exactly two, (b) more than two, and (c) between two and five inclusive. If convenient use technology to find the probabilities. P(2) = (Round to the nearest thousandth as needed.) P(x > 2) = (Round to the nearest thousandth as needed.) P(2 x 5)= (Round to the nearest thousandth as needed.)
Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

a) There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

b) There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

c) There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this exercise using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 students are randomly selected, so n = 10.

23% of college students say they use credit cards because of the rewards program. This means that \pi = 0.23

(a) exactly two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities of these events must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733

P(X = 1) = C_{10,1}.(0.23)^{1}.(0.77)^{9} = 0.2188

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0733 + 0.2188 + 0.2942 = 0.5863

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.5863 = 0.4137

There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

(c) between two and five inclusive.

This is

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,3}.(0.23)^{5}.(0.77)^{5} = 0.0439

So

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2942 + 0.2343 + 0.1225 + 0.0439 = 0.6949

There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

You might be interested in
Archaeologists attempt to reconstruct past ways of life by examining preserved bones, the ruins of buildings, and artifacts such
jok3333 [9.3K]
I thing b I'm not sure tho
5 0
3 years ago
A contractor charges $1,200 for 100 swat feet of roofing installed. At this rate, how much does it cost to have 1,000 square fee
Oliga [24]

Answer:

12000

Step-by-step explanation:

1200=100

x=1000

x=100*1200/100

3 0
3 years ago
For what value of b in the equation (2z + b)(z − 3) = 0 will a solution for z be −4?
bazaltina [42]
( - 8 +  b )( - 4 - 3 ) =  0;
( - 8 + b )( - 7 ) = 0 ;
-8 + b = 0;
b = 8.
7 0
3 years ago
Triangle X Y Z is shown. Angle X Z Y is a right angle. Angle Z X Y is 60 degrees and angle X Y Z is 30 degrees. The length of hy
vladimir1956 [14]

Answer:

StartFraction StartRoot 3 EndRoot Over 3 EndFraction

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

we know that

In the right triangle XYZ

cos(Y)=\frac{ZY}{XY} ---> adjacent side divided by the hypotenuse

substitute the values

cos(30\°)=\frac{ZY}{4}

Remember that

cos(30\°)=\frac{\sqrt{3}}{2}

so

substitute

\frac{\sqrt{3}}{2}=\frac{ZY}{4}

ZY=(4)\frac{\sqrt{3}}{2}

ZY=2\sqrt{3}\ units

step 2

sin(Y)=\frac{XZ}{XY} --> opposite side divided by the hypotenuse

substitute the values

sin(30\°)=\frac{XZ}{4}

Remember that

sin(30\°)=\frac{1}{2}

so

\frac{1}{2}=\frac{XZ}{4}

XZ=2\ units

step 3

tan(Y)=\frac{XZ}{ZY} --> opposite side divided by adjacent side

substitute the values

tan(Y)=\frac{2}{2\sqrt{3}}

tan(Y)=\frac{1}{\sqrt{3}}

Simplify

tan(Y)=\frac{\sqrt{3}}{3}

so

StartFraction StartRoot 3 EndRoot Over 3 EndFraction

7 0
3 years ago
Read 2 more answers
What is the measure of E?
IceJOKER [234]
You can get E real quick
how? you know that D is 90 and f is given 66 and you know that D+E+F=180 so E=180-(90+66) which gives us 24
6 0
3 years ago
Other questions:
  • 9/11 =?/22 what is the answer
    13·2 answers
  • A student simplified a fraction to 2/5 by removing the common factors of 2 and 7. What was the original fraction?
    5·1 answer
  • Answer quick please brainliest (:
    15·2 answers
  • How do u simplify √2/√3x
    10·1 answer
  • Explain how to wrie a function rule from the table then write one
    8·1 answer
  • Tammy needs at least an 85% in order to pass<br> her chemistry class.
    14·1 answer
  • In the diagram, JKLM~EFGH. Find the scale factor of JKLM TO EFGH. Plz help
    12·1 answer
  • Write a rule to describe each reflection.<br><br> Rule:r(?) (x,y)=(?)
    14·1 answer
  • 3,052/2,8 Alguien me ayuda porfa
    7·1 answer
  • A circle has a diameter of 4 in. What is the Radius and Circumference
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!