<span>Total lot - house -other side
=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)
=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)
=16 ft 6 in
Convert to inches: </span>16 ft x 12 in/ft)+ 6 in= Total in inches<span>192 in + 6 in= Total in inches
198 in= Total in inches
Check: One side + house + other side = Lot width
(5 ft 5 in)+(34 ft 10 in)+(16 ft 6 in)=Lot width
56 ft 9 in=Lot width, which equals the given.</span>
Answer:Area of part 1:
A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2
Area of part 2:
A2=length*width=(8+2)*1=10 ft2
Area of part 3:
A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2
Total area of the reactangle : A=16*8=128 ft2
Total area of the nonshaded region : 128-41=87 ft2
Step-by-step explanation: Plz make brainliest
Answer:
12
Step-by-step explanation:
if h=5
then <u>h+7</u> = <u>5+7</u> = <u>12</u>
Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.