A student simplified a fraction to 2/5 by removing the common factors of 2 and 7. What was the original fraction?

Helppp pleasee it’s needed quick points

Dominik [7]

hope this helps :)

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6 0

2 years ago

FIRST RIGHT ANSWER GETS BRAINLLEST If you spin the spinner below 20 times, which of the following outcomes are reasonable? Selec

erik [133]

Answer:

B) Lands on red 6 times

C) Lands on yellow 4 times

Step-by-step explanation:

The rest are way too much/too little for their predicted probability.

7 0

3 years ago

Read 2 more answers

Please include work! :)

UNO [17]

Answer:

m = 13.

Step-by-step explanation:

Recall that adding logarithmic equations, (ex: log a + log b) is the same as log (a·b). Therefore:

log 12 + log 5 = log (4m + 8)

log (12·5) = log (4m + 8)

log (60) = log (4m + 8) **Ignore 'Log' to solve for 'm'

60 = 4m + 8 **Subtract both sides by 8

52 = 4m **Divide both sides by 4

m = 13.

6 0

3 years ago

Find the first four terms of the sequence given by the following. aₙ=43-3(n-1) n=1,2,3. . .

Serggg [28]

Given :-

The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

The first four terms of the sequence.

Solution :-

The given expression is $/$

→ aₙ=43-3(n-1)

where n > 0

Finding the first term :

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

Finding the second term :

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

Finding the third term :

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

Finding the fourth term :

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

Hence the first four terms of the sequence are 43 , 40 , 37 and 34 .

I hope this helps . Let me know if you need further clarification .

7 0

2 years ago

A new car is purchased for $17,000 and over time its value depreciates by one half every 3 years. What is the value of the car 1

Jet001 [13]

Answer:

The answer is "$238".

Step-by-step explanation:

Current worth $= \$ 17,000$

depreciates by $\frac{1}{2}$ in 3 years.

time= 19 years

depreciates rate=?

Using formula:

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$\to A_t=A_0(1-\frac{r}{100})^t$

calculates depreciate value in 3 year $= \frac{1}{2} \times 17,000$

$= 8,500$

so,

$A_t=8,500\\\\A_0=17,000\\\\t=3\ years$

$\to A_t=A_0(1-\frac{r}{100})^t\\\\\to 8,500= 17,000(1-\frac{r}{100})^3\\\\\to \frac{8,500}{17,000}= (1-\frac{r}{100})^3\\\\\to \frac{1}{2}= (1-\frac{r}{100})^3\\\\\to (\frac{1}{2})^{\frac{1}{3}}= (1-\frac{r}{100})\\\\\to 0.793700526 = (1-\frac{r}{100})\\\\\to \frac{r}{100} = (1-0.793700526)\\\\\to \frac{r}{100} = (1-0.8)\\\\\to r= 0.2 \times 100 \\\\\to r= 20 \%$

depreciates rate= 20%

$\to \text{Worth= Current worth}(1- \frac{\text{depreciates rate}}{100})^{time}$

$= \$ 17,000 (1- \frac{20}{100})^{19}\\\\= \$ 17,000 (1-0.2)^{19}\\\\= \$ 17,000 (0.8)^{19}\\\\= \$ 17,000 \times 0.014\\\\= \$ 238$

4 0

3 years ago

Read 2 more answers