Question

A solid right pyramid has a regular hexagonal base with an area of 7.4 units2. The pyramid has a height of 6 units.

Answer 1

Answer:

V = 14.8 u³

Step-by-step explanation:

The formula of a volume of a pyramid:

$V=\dfrac{1}{3}BH$

B - area of a base

H - height

We have B = 7.4, and H = 6.

Substitute:

$V=\dfrac{1}{3}(7.4)(6)=\dfrac{44.4}{3}=14.8\ u^3$

Answer 2

Answer:

14.8 unit^3.

Step-by-step explanation:

The volume = 1/3 * height * the area of the base

= 1/3 * 6 * 7.4

=  2 * 7.4

= 14.8 unit^3.