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Rom4ik [11]
2 years ago
11

First to answer will be the brainliest I need the answer ASAP

Mathematics
1 answer:
tatuchka [14]2 years ago
3 0
6b+2 I think I combined them and that’s what I got
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Plz help me with this obviously i'm in school so i need the answer fast before the teacher sees me.
Katena32 [7]

Your answer is either C or D. But I strongly believe that the answer would possibly be C.


-Anime

4 0
3 years ago
Can dilations be used to form scale copies of a figure?
Inessa [10]

Answer:

sometimes

Step-by-step explanation:

There are several ways that dilation is used in real life. Here are several:

In graphic design. I actually do some graphic design, and I use dilation a lot. It is common to dilate photos to fit the space that you want it to fit.

In police work and crime investigation. Detectives and police dilate photos to see smaller details and evidence.

In architecture. It is normal for architects to make a prototype of their design or building. In order to make the building true to the prototype, they must dilate the scale and measurements.

In the doctor's office. Dilation is used in eye exams so that the eye doctor can view the patient's eye better. After a while it will slowly reduce in size and return back to normal.

3 0
1 year ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
2 years ago
is the relationship between the side length of a square and the area of the square an example of a function?
vekshin1
Yes. to find the area of a square when you know one side "s", you simply square that side since the area is equal to the base times the height, and the base and height will always be equal in a square since the sides are equal:

A = s^2 

Represented in a function form:

f(s) = s^2

This means whatever you plug in for s, you will square it to get the area.
3 0
2 years ago
If Brian biked at an average speed of 12.2 miles per hour for 1.45 hours, you can find the total distance by multiplying
gavmur [86]

Answer:

First, multiply the numbers. Then count the number of decimal places in each factor. Place the decimal in the product so the product has the same number of decimal places as both factors combined.

Step-by-step explanation:

Did it on Edg.2020

7 0
2 years ago
Read 2 more answers
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