Answer:
p = 1.5 and q = 9
Step-by-step explanation:
Expand the right side then compare the coefficients of like terms on both sides, that is
4(x + p)² - q ← expand (x + p)² using FOIL
= 4(x² + 2px + p²) - q ← distribute parenthesis
= 4x² + 8px + 4p² - q
Comparing coefficients of like terms on both sides
8p = 12 ( coefficients of x- terms ) ← divide both sides by 8
p = 1.5
4p² - q = 0 ( constant terms ), that is
4(1.5)² - q = 0
9 - q = 0 ( subtract 9 from both sides )
- q = - 9 ( multiply both sides by - 1 )
q = 9
Answer:
<u>less</u><u> </u><u>than</u><u> </u><u>5</u><u>%</u>
Step-by-step explanation:
In the USA <u>less</u><u> </u><u>than</u><u> </u><u>5</u><u>%</u><u> </u> of children under the age of 11 study a language other than English at school
Hopefully this helped- have a good day)
a - length of side of a square
t - length of side of a triangle
The perimeter of a square: 
The perimeter of a triangle: 
We have the area of a triangle: 
The formula of an area of an equilateral trinagle: 
Substitute:
<em>multiply both sides by 4</em>
<em>divide both sides by
</em>

The perimeter of a triangle: 
Substitute to the formula of a perimeter of a square:
<em>divide both sides by 4</em>

The formula of a diagonal of a square: 
Substitute:

Answer:
what do you call a white person having a seizure...............................milk-
shake
Step-by-step explanation:
Answer:
70°
Step-by-step explanation:
Connect the center of the circle with endpoints of the chord. Let the center of the circle be point O and endpoints of the chord be points A (let point A lie on the tangent line too)and B.
From the figure, central angle AOB has the measure of 220°.
Consider triangle AOB. This triangle is isosceles triangle because OA and OB are both radii. In this triangle the measure of angle AOB is 360° - 220° = 140°.
Angles OAB and OBA are angles adjacent to the base AB, so they are congruent. The sum of the measures of all interior angles in triangle is always 180°, so
m∠OAB + m∠OBA + m∠AOB = 180°
m∠OAB = m∠OBA = 1/2 (180° - 140°)
m∠OAB = 20°
Since drawn line is tangent line, then OA is perpendicular to this tangent line and
x° = 90° - 20°
x° = 70°