If the side of square P is x and the side of square Q is y, we have x+y=26. In addition, 3*the perimeter of P+8*4y=3*4x+32y=12x+32y=492.
We have
x+y=26
12x+32y=492
Multiplying the first equation by -12 and adding it to the second, we get
20y=180 and dividing by 20 we get y=9. Plugging it into the first equation, we get 26-9=17=x. Since the area of square P is x^2 and Q is y^2,
x^2+y^2=19^2+7^2=410=the sum of the squares
Answer:
0.987750947 miles
Step-by-step explanation:
first you find how many inches are in a mile and there are 63360 inches in a mile
2nd you minus 63360 - 776.1 = 62583.9 then you get 62583.9 and put it in miles and your answer is 0.987750947 miles
If half the sum of the bases is multiplied by the height, then that is the area of the trapezoid.
I believe this is the correct wording.
I am pretty sure these statements are created by taking the last part of the statement and pairing it with the “if” and the first part of the statement and pairing it with a “then” to make a complete statement.
I hope this helps! :)
Comparing to the standard equation, the parabola with a vertex at (-2,0) is given by:
y = (x + 2)²
<h3>What is the equation of a parabola given it’s vertex?</h3>
The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
In this problem, we have that h = -2 and k = 0, and all the options have leading coefficient a = 1, hence the equation is:
y = (x + 2)²
More can be learned about the equation of a parabola at brainly.com/question/17987697
Answer:
Step-by-step explanation:
we know that
In this problem we have a exponential function of the form
where
x ----> is the number of years since 2009
y ----> is the population of bears
a ----> is the initial value
b ---> is the base
step 1
Find the value of a
For x=0 (year 2009)
y=1,570 bears
substitute
so
step 2
Find the value of b
For x=1 (year 2010)
y=1,884 bears
substitute
The exponential function is equal to
step 3
How many bears will there be in 2018?
2018-2009=9 years
so
For x=9 years
substitute in the equation
