Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
Step-by-step explanation:
4x + 2y = 10 --------(1)
2x + 3y = 33 -----------(2)
Multiply 2 with eq. (1) and 4 with eq. (2)
8x + 4y = 20 ____________(3)
8x + 12y = 132 ______(4)
Subtracting (3) from (4),
8x + 4y = 20
- 8x -12y = -132
----------------------
0 -8y = -112
y = 112/8
y = 4 is the answer.
Putting the vakue of y in eq. (2),
2x + 12 = 33
2x = 33-12
2x = 21
x = 21/2 is the answer.
Answer: 25
Step-by-step explanation: When you divide exponents with the same base, you can subtract the exponents. It becomes 5^4-2, which is 5^2, which is 25
Both B and D are 100% correct. I'd flip a coin because there is no way of answering that one 100% correctly. <span />
