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3 years ago

Saving?

Mathematics

1 answer:

nikitadnepr [17]3 years ago

7 0

Answer:

A man borrows * 8000

He agrees to repay with a total interest of 1360 in 12 monthly instalments.

Each instalment being less than the preceding one by * 40

= $\frac{12}{1360}$ x 40

= 12 x 34

= 408 (Ans)

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Help plz this is due late so plz help me

Gekata [30.6K]

Answer:

1st option

Step-by-step explanation:

Each exponent inside the bracket is multiplied by the exponent outside , that is

$(\frac{2^{5} }{3^{2} )} ^{4}$

= $\frac{2^{5(4)} }{3^{2(4)} }$

= $\frac{2^{20} }{3^{8} }$

7 0

2 years ago

Are there any linear quantities in the chart shown? And if so, what is the slope of said pairs?

VashaNatasha [74]

The chart does not represent a linear quantity

<h3>How to determine if there are linear quantities in the chart shown?</h3>

From the chart, we have the following coordinates

(x, y) = (0.10, 0.14), (0.50, 0.32), (1.00, 0.46), (1.70, 0.59) and (2.00, 0.63)

To determine if the chart is a linear quantity, we simply calculate the slope using the coordinates.

The slope is calculated as:

m = (y2 - y1)/(x2 - x1)

So, we have:

m = (0.32 - 0.14)/(0.50 - 0.10) = 0.45

m = (0.46 - 0.32)/(1.00 - 0.50) = 0.28

In the above computations, the calculated slopes are not equal

Hence, the chart does not represent a linear quantity

Read more about linear equations at:

brainly.com/question/1884491

#SPJ1

7 0

2 years ago

What is the perimeter of the fifth square in this pattern?

Rom4ik [11]

I think its 144 because its the fifth square

7 0

3 years ago

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago

Evaluate please like pretty please

yaroslaw [1]

It would be zero because you can’t raise 0 to any positive power.

8 0

2 years ago