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3 years ago

If you could repeat the lab and make it better, what would you do differently and why?

Chemistry

2 answers:

inysia [295]3 years ago

5 0

Well what are u doing in the lab and what is something that u did wrong so u can approve

nignag [31]3 years ago

5 0

Hello, I will state the answer below.

If I could repeat the lab and make it better... I would make it where every mistake we've made, and improve it. If we didn't do this, the lab would be a mess and wouldn't be successful.

Hope this helps!!

⌨ Have a good day! ⌨

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5.00 g of an unknown compound was dissolved in 250.0 mL of water. The unknown compound was found to be a non-electrolyte and the

Zielflug [23.3K]

Answer:

This unknown compound has a molar mass of 33.74g/mole

Explanation:

Step 1: Given data

The formula for the osmotic pressure is:

π = MRT = 14.5 atm

⇒ with M = Concentration of the solution

⇒ with R = gas constant = 0.08206 L atm / mol K

⇒ with T = absolute temperature (in Kelvin) = 298K

Step 2: Calculate concentration

M = π/ RT

M = 14.5 / (0.08206 * 298)

M = 0.593 M this is 0.593 moles per L

Step 3: Calculate number of moles

Since the volume is only 0.250 L, the amount of moles is:

0.593 * 0.250 L = 0.1482 moles

Step 4: Calculate molar mass

The molar mass is : mass / moles

Molar mass of this unknown compund = 5g / 0.1482 moles = 33.74 g/mole

This unknown compound has a molar mass of 33.74g/ mole

4 0

3 years ago

Match the part of the wave to the diagram

erik [133]

Answer:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5.

Explanation:

The first high part is Q4, then the low part is Q7, the following high part is Q6, and the energy moving from the next two high points is Q5 because of the diagram.

5 0

3 years ago

what is the difference between a chemical bonds formed in the molecules of 02 and the chemical bonds formed in crystals of a NaC

Jobisdone [24]

Answer:

O2 is a covalent substance while NaCl is an ionic substance

Explanation:

In O2 molecule, the bond is between 2 oxygen atoms which are non - metals. Thus, this is a covalent bond since it involves 2 non metals.

Whereas, for the NaCl molecule, the bond is between a metal sodium (Na) and a non metal Chloride(Cl) and thus we can say this is an ionic bond.

Thus the difference is that O2 is a covalent substance while NaCl is an ionic substance.

8 0

3 years ago

Complete and balance the molecular equation, including phases, for the reaction of aqueous sodium sulfate, Na2SO4, and aqueous b

expeople1 [14]

The complete chemical reaction of aqueous Sodium sulfate and aqueous Barium nitrate is

$Na_{2} SO_{4} (aq) + Ba(NO_3)_2(aq) -\ \textgreater \ BaSO_4(s) + 2NaNO_3(aq)$

The right side and the left side of the reaction have equal number of elements, therefore it is balanced.

5 0

3 years ago

Read 2 more answers

1. A student needs to make 80mL of a 4.5 x 10^-3 M solution of H_3PO_4 (mm = 98) from solid. Describe how the student would do t

slamgirl [31]

Answer:

1. 35 mg of H₃PO₄

2. 27 mol AlF₃; 82 mol F⁻

3. 300 mL of stock solution.

Explanation:

1. Preparing a solution of known molar concentration

Data:

V = 80 mL

c = 4.5 × 10⁻³ mol·L⁻¹

Calculations:

(a) Moles of H₃PO₄

Molar concentration = moles of solute/litres of solution

c = n/V

n = Vc = 0.080L × (4.5 × 10⁻³ mol/1 L) = 3.60 × 10⁻⁴ mol

(b) Mass of H₃PO₄

moles = mass/molar mass

n = m/MM

m = n × MM = 3.60 × 10⁻⁴ mol × (98 g/1 mol) = 0.035 g = 35 mg

(c) Procedure

Dissolve 35 mg of solid H₃PO₄ in enough water to make 80 mL of solution,

2. Moles of solute.

Data:

V = 4900 mL

c = 5.6 mol·L⁻¹

Calculations:

Moles of AlF₃ = cV = 4.9 L AlF₃ × (5.6 mol AlF₃/1L AlF₃) = 27 mol AlF₃

Moles of F⁻ = 27 mol AlF₃ × (3 mol F⁻/1 mol AlF₃) = 82 mol F⁻.

3. Dilution calculation

Data:

V₁= 750 mL; c₁ = 0.80 mol·L⁻¹

V₂ = ? ; c₂ = 2.0 mol·L⁻¹

Calculation:

V₁c₁ = V₂c₂

V₂ = V₁ × c₁/c₂ = 750 mL × (0.80/2.0) = 300 mL

Procedure:

Measure out 300 mL of stock solution. Then add 500 mL of water.

3 0

4 years ago