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The most stable isotope of Chromium is ⁵²Cr with a mass of 51,9405 amu.
We know that because of the information that we can find in the periodic table. Which information is that? The atomic weight of the element. Atomic weights are calculated taking into account the relative abundances of each isotope of the element. The isotope that is the most abundant one will influence more the atomic weight that is found in the periodic table.
For chromium, its atomic weight, that we can find on the periodic table, is 51,99 amu. The isotope weight that is nearest to this atomic weight is ⁵²Cr with a mass of 51,9405 amu, so that will be the most stable isotope.
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4333
Answer:
0.533 mol O2
Explanation:
4 Fe3O4 + O2 -> 6 Fe2O3
1 mol O2 -> 6 mol Fe2O3
x -> 3.2 mol Fe2O3
x = (3.2 mol Fe2O3 * 1 mol O2)/ 6 mol Fe2O3
x= 0.533 mol O2
Answer:
The empirical formula of the hydrocarbon is CH.
Explanation:
The following data were obtained from the question:
Mass of hydrocarbon = 2.9 mg
Mass of CO2 = 9.803 mg
Mass of H2O = 2.006 mg
Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.
This is illustrated below:
Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol
Mass of CO2 = 9.803 mg
Mass of C in the compound =?
Mass of C in the compound =
12/44 x 9.803
= 2.674 mg
Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O = 2.006 mg
Mass of H in the compound =
2/18 x 2.006
= 0.223 mg
Finally, we shall determine the empirical formula of the hydrocarbon as follow:
Carbon (C) = 2.674 mg
Hydrogen (H) = 0.223 mg
Divide by their molar mass
C = 2.674 /12 = 0.223
H = 0.223 / 1 = 0.223
Divide both side by the the smallest
C = 0.223/0.223 = 1
H = 0.223/0.223 = 1
Therefore, the empirical formula of the hydrocarbon is CH.
In which region is the substance in both the solid phase and the liquid phase ?
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