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slavikrds [6]
3 years ago
5

Which property of gases is explained by the process of diffusion?

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
6 0

Answer:

their ability to fill the available volume of a container

Explanation:

Diffusion is the movement of gas molecules from a region of higher concentration to a region of lower concentration. Gasses fill up the volume of a container because gas molecules spread out in empty space. By so doing they fill up the volume of the container. This spreading out is caused by diffusion. Hence this property is explainable by diffusion.

Sindrei [870]3 years ago
3 0

Answer: D. Their ability to fill the available volume in a container. I hope this is right.

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What is a solution?
Mama L [17]
The correct answer is a solute and a solvent

A solution is any homogenous mixture of two or more substances. It does not necessarily have to be liquid or gaseous. 
7 0
3 years ago
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
4 0
3 years ago
Read 2 more answers
A 253 g block of wood has the following dimensions: Length 15.24 cm Width 6.64 cm Height 3.56 cm What is the density of the wood
yanalaym [24]

Answer:

0.7 g/cm³

Explanation:

<em>hey there,</em>

<em />

< The formula for density is p = \frac{m}{v}  where m = mass, v = volume, and p = density. An easy way to remember the formula is density equals love. I found this easy to remember because p = ♡ and when you think about it, if you split the heart in half through the middle like a fraction, it will make \frac{m}{v} (if you don't understand what I'm saying, try writing it out and you will be able to see what I'm talking about!)

We already know that the block is 253 g so the mass is 253 g.

To find the volume, always multiply the 3 values width, length, and height whenever you are trying to find the volume of a block.

15.24 cm x 6.64 cm x 3.56 cm = 360.25 cm³

Now plug it into the formula.p = \frac{m}{v}=\frac{253}{360.25} = 0.7 g/cm³ >

<u>Hope this helped! Feel free to ask anything else.</u>

4 0
3 years ago
A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final
Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:

  • P₁V₁=P₂V₂

Where in this case:

  • P₁ = 159 atm
  • V₁ = 463 L
  • P₂ = ?
  • V₂ = 817 L

We <u>input the given data</u>:

  • 159 atm * 463 L = P₂ * 817 L

And <u>solve for P₂</u>:

  • P₂ = 90.1 atm

The final pressure is 90.1 atm.

6 0
3 years ago
How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
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