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GrogVix [38]
3 years ago
8

The midpoint of CD is E(–1, 0). One endpoint is C (5, 2). What are the coordinates of the other endpoint?. . Explain step by ste

p please I'm not good at endpoints :\
Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

is there a graph or something? I will come back to finish this ok. ok

Step-by-step explanation:

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What is fifty five hundredths plus twenty five hundredths
Maksim231197 [3]
That would be 8000.. hope it helps
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3 years ago
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PLZZ ANSWER THIS AS SOON AS POSSIBLE!!!!
alexandr402 [8]

Answer:

y = -9.3

if they are complementary it is 45 degrees

if they are supplementary it is 90 degrees

Step-by-step explanation:

-12.7 = y -3.4

-12.7 + 3.4 = y -3.4 + 3.4

-9.3 = y

complementary angles equal to 90 degrees

supplementary angles equal to 180 degrees

vertical angles have same degrees

so 90/2= 45

180/2 =90

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3 years ago
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Help me please. Fill in the green box
faust18 [17]
According to the euclidean triangle theorem
9 = z² / 13
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3 0
3 years ago
Use the drawing tool(s) to form the correct answers on the provided grid. Consider the function g. For the x-value given in the
NeX [460]

Answer:

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

Step-by-step explanation:

g(x) = -3(1/2)^x

Putting values of x

x     g(x)

-2    -3(1/2)^-2 = -12

-1     -3(1/2)^-1 = -6

0     -3(1/2)^0 = -3

1      -3(1/2)^1 = -3/2

Now, making the graph we will plot

(-2,-12), (-1,-6), (0,-3) and (1,-3/2)

The graph is shown in figure below.

8 0
3 years ago
Two similar prisms have heights 4 cm and 10cm what is the ratio of their surface areas
Slav-nsk [51]
Let k be the scale factor relating two similar prisms P_{1} and P_{2}, such that for corresponding parts of prisms P_{1} and P_{2} (for heights, in particular) we have k= \frac{height\  of \ P_{1} }{height \ of\  P_{2} }. In our case k= \frac{4}{10} = \frac{2}{5}.
For surfaces area we have \frac{Surface \ area \ of \  P_{1} }{Surface \ area \ of \  P_{2}} = k^{2} =( \frac{2}{5} )^{2}= \frac{4}{25}.
So, the right answer is 4:25 (choice B)



4 0
3 years ago
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