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scoundrel [369]
3 years ago
10

A wire of length 7x is bent into the shape of a square. Express the area A of the square as a function of z.

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

7×

4+4+4+4

4+4=8

4+4=8

8+8=16

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GIVING OUT BRAINLIEST!! All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessari
Vsevolod [243]

Answer:

flour = 11.5, sugar has to be equal to 2.75 pounds.

Step-by-step explanation:

your 2 inequalities are:

2x + 3y <= 40

y <= 2x + 6

the second equation can be shown as:

-2x + y <= 6

solve the equality portion of these 2 inequalities.

those are the following equations:

2x + 3y = 40

-2x + y = 6

add these equations together and solve for y to get

y = 11.5

that appears to be a break even point.

when y = 11.5, the first inequality is solved as follows:

2x + 3y <= 40

replace y with 11.5 and the inequality becomes:

2x + 34.5 <= 40

solve for x to get

x <= 2.75

when y = 11.5, the second inequality is solved as follows:

-2x + y <= 6

replace y with 11.5 and the inequality becomes:

-2x + 11.5 <= 6

solve for x to get x >= 2.75

this indicates that, when y = 11.5, x has to be equal to 2.75.

both constraints are satisfied.

6 0
3 years ago
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Find all square roots of 8100?
Nikitich [7]
The Square Root Of 8100 Is 90. That Will Be The Only Square Root Because The Square Root Of 90 Is A Decimal So You Would Stop There.
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What is the value of x in the diagram below?
otez555 [7]

The cosine of 30° is √3 / 2.

Since cosine is Adjacent over Hypotenuse, Hypotenuse = (2 / √3) * 9 = 18 / √3.

The cosine of 45° is √2 / 2.

Therefore, X = (2 / √2) * (18 / √3) = 36 / √6 = 18 / √1.5 = C

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4 years ago
What is the solution to the system of equations graphed below?
umka2103 [35]

Answer:

a

Step-by-step explanation:

the two lines intercept at 1,-2

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Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

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Por lo tanto, la longitud del otro cateto es 9 cm

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