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Dennis_Churaev [7]

2 years ago

9

At a fair, each person can spin two wheels of chance. The first wheel has the numbers 1, 2, and 3. The second wheel has the lett

ers A and B.
Explain how you know if this game of chance is based on simple or compound probability.

1 answer:

IgorC [24]2 years ago

5 0

Answer:

4

Step-by-step explanation:

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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2 years ago

Write the ratio as a fraction in simplest form. 32:42

maks197457 [2]

16/21 is your answer

You can take a 2 out of both numbers to get your answer

I hope this helped! :)

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tatyana61 [14]

Answer:

Radius= 8.86 m

Step-by-step explanation:

Pie x r^2 x 0.7= 172.48

Pie x r^2= 246.4

r^2= 78.43

R= square root of 78.43

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HELP PLEASE THANK YOU SO SO SO MUCH <3

pashok25 [27]

Just copy this down. you welcome

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