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Alona [7]
2 years ago
10

Find an equation in slope intercept form of a line having slope 6 and y-intercept 2

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0

Answer:

<h2>y = 6x + 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the slope <em>m = 6</em>, and the y-intercept <em>b = 2</em>.

Substitute:

y=6x+2

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576

Step-by-step explanation:

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I need help on to wich expresion has the least value 10 second challenge
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Answer:

The first one.

Step-by-step explanation:

Both of the equations in the parenthesis have the same value, and 1/2 isn't as much as a whole.

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7 0
3 years ago
Is 16:14 in 64:60 eqiluvant
Elanso [62]

16: 14 - divide by 2

16/2= 8 , 14/2=7

64:60- divide by 4

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3 years ago
Under a certain transformation T, AA'BC' is the image of AABC. The perimeter of AA'B'C' is twice the perimeter of ABC. What kind
Anika [276]

The dimensions of the image are twice the dimensions of the preimage,

which indicates that the transformation is a dilation.

  • The transformation <em>T</em> is; <u>a dilation transformation with a scale factor of 2, D₂</u>

Reasons:

The transformation applied to ΔABC = T

The image of ΔABC following the transformation, T = ΔA'B'C'

The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC

Therefore, we have;

A'B' + B'C' + A'C' = 2 × (AB + BC + AC)

Which gives

A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC

By similar triangles, we have the ratio of corresponding sides as follows;

\displaystyle \frac{AB}{A'B'}  = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}

Which gives;

\displaystyle \frac{AB}{A'B'}  = \frac{AB}{2 \cdot AB} = \frac{1}{2}

A'B' = 2·AB

Therefore;

  • Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and <em>T</em> is <u>a dilation transformation with a scale factor of 2, D₂</u>

Learn more about dilation transformation here:

brainly.com/question/2458912

3 0
2 years ago
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