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ddd [48]
3 years ago
6

The swimming pool is open when the high temperature is higher than 20^\circ\text{C}20 ? C20, degree, C. Lainey tried to swim on

Monday and Thursday (which was 333 days later). The pool was open on Monday, but it was closed on Thursday. The high temperature was 30^\circ\text{C}30 ? C30, degree, C on Monday, but decreased at a constant rate in the next 333 days.
Mathematics
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

30-3d\leq 20

Step by step explanation:

Let d represent the rate of temperature decrease in degrees Celsius per day from Monday to Thursday.  

As temperature decreased at a constant rate in the next 3 days, so the rate of temperature will decrease 3d degree Celsius in 3 days.  

We are told that the pool was open on Monday. The high temperature was 30^{\circ}{\text{C} on Monday. So the decrease in temperature from Monday to Thursday will be 30-3d.

We have been given that the swimming pool is open when the high temperature is higher than 20^{\circ}{\text{C}.

As the pool was closed on Thursday. This means that temperature on Thursday was less than or equal to 20 degree Celsius. We can represent this information in an inequality as:

30-3d\leq 20

Therefore, the inequality 30-3d\leq 20 can be used to determine the rate of temperature decrease in degrees Celsius per day, d, from Monday to Thursday.

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