Answer:

or

Considering ![\theta \in (0, 2\pi]](https://tex.z-dn.net/?f=%5Ctheta%20%5Cin%20%280%2C%202%5Cpi%5D)

or

Step-by-step explanation:

We have:

Therefore,

or

---------------------------------

or

Answer:
x = 30m
Step-by-step explanation:
<u>GIVEN :-</u>
There are 2 right-angled triangles.
In the triangle on the right side ,
- Hypotenuse = 26m
- Base = 10m
In the triangle on the left side ,
<u>TO FIND :-</u>
- Length of the common perpendicular to both triangles.
- Length of the hypotenuse of the triangle on the left side.
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
.
<u>SOLUTION :-</u>
In the triangle on the right side ,

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.
In the triangle on the left side ,

∴ x = 30m
Answer:
42
Step-by-step explanation:
4+6 = 10
10+7 = 17
17+2 = 19
19+9 = 28
28+2 = 30
30+9 = 39
39+3 = 42
The intercept method of graphing is quick and easy.
Find the x-intercept by setting y = 0 and solving for x:
y+1=1/3(x−3) => 0<span>+1=1/3(x−3)
Multiply both sides by 3: 3 = x - 3. Then x = 6, and the x-int. is (6, 0).
Find the y-int by setting x = 0 and solving for y:
</span><span>y+1=1/3(0−3)
Mult both sides by 3: 3y+3 = -3, so that 3y = -6, and y = -2.
Then the y-intercept is (0,-2).
Plot these 2 points. Then draw a line thru them.</span>