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xeze [42]
3 years ago
7

What are the factors of x2 − 25?

Mathematics
1 answer:
german3 years ago
3 0

Answer:

)x + 5)(x - 5)

Step-by-step explanation:

x² - 25 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b), thus

x² - 25 = x² - 5² = (x + 5)(x - 5)

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Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?
mafiozo [28]

Answer:

13x = 39

x=3

y=10

5 0
1 year ago
Which of the following is not a way to represent the solution of the inequality 2(x − 2) less than or equal to 2?
Nezavi [6.7K]
The answer is A  A number line with a closed circle on 3-
8 0
2 years ago
Read 2 more answers
I need help with this asap!!! pls​
Len [333]

Answer:

ok so the answers are for all of them number 1-6 sorry

Step-by-step explanation:

1) unite rate

2) constant rate

3) proportional relationship

4) ordered pair

5) greater than

6) less than

hope this helps girlyy<33

4 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Yuki works at a garden store. She is stacking 40-pound bags of soil. Use the equation w=40b to find the total weight, w, of 5 ba
NeTakaya

Answer:

w= 40b

w=40× 5

w=200

......

4 0
2 years ago
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