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4 years ago

What is the volume of the triangular prism? A) 480 cm3 B) 960 cm3 C) 1200 cm3 D) 1920 cm3

Mathematics

2 answers:

tiny-mole [99]4 years ago

6 0

The answer should be D.

Gwar [14]4 years ago

5 0

Answer: 960

Step-by-step explanation:

960 cm3 The triangular base has area

(12)(16) = 96. Multiply 96 by the height, 10.

V = 1/2(16)(12)(10) = 960

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3 years ago

In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%

lions [1.4K]

Answer:

$n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59$

And rounded up we have that n=350

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\aht p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.05$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59$

And rounded up we have that n=350

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The numbers that go evenly into 24 are 1, 2, 3, 4, 6, 8, 12, and 24. For 27, those numbers are 1, 3, 9, and 27.

The common factors between two numbers are numbers that go into both numbers evenly. Looking through the lists for 24 and 27, we see that 1 and 3 are their common factors. The greatest common factor is, of course, the largest of these, so the greatest common factor of 24 and 27 is 3.

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