Let x be the number of people that can be seated.
The value of x is some number 0 or greater, such that this number is a whole number (we can't have half a person). This means that

which is the same as saying

The instructions state that we can seat up to 1200 people. This is the max capacity. We can't go over this amount. So we will also have

indicating that x can be less than 1200 or equal to 1200.
So putting the two inequalities together, we get

Note: if you haven't learned about compound inequalities yet, then the teacher may only want
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as the answer.
Answer:
Given A triangle ABC in which
∠C =90°,∠A=20° and CD ⊥ AB.
In Δ ABC
⇒∠A + ∠B +∠C=180° [ Angle sum property of triangle]
⇒20° + ∠B + 90°=180°
⇒∠B+110° =180°
∠B =180° -110°
∠B = 70°
In Δ B DC
∠BDC =90°,∠B =70°,∠BC D=?
∠BDC +,∠B+∠BC D=180°[ angle sum property of triangle]
90° + 70°+∠BC D =180°
∠BC D=180°- 160°
∠BC D = 20°
In Δ AC D
∠A=20°, ∠ADC=90°,∠AC D=?
∠A + ∠ADC +∠AC D=180° [angle sum property of triangle]
20°+90°+∠AC D=180°
110° +∠AC D=180°
∠AC D=180°-110°
∠AC D=70°
So solution are, ∠AC D=70°,∠ BC D=20°,∠DB C=70°
You multiply $15 by 23 which is 345. Then you multiply 345 by 52 for there is 52 in a year. The answer $17940.
Answer:
(2.25 , 0.75)
Step-by-step explanation:
solution is where the graphs intersect each other
3/4 = - x + 3
-x = 3/4 -3 = -2 1/4
x =2 1/4
Answer:
9x^2 -49
Step-by-step explanation:
We recognize that this is of the form
(a+b)(a-b) = a^2 - b^2
3x = a and 7 =b
(3x)^2 - 7^2
9x^2 -49