This is a GCF problem,
find the GCF of 36 and 27. To do this, list out the factors for each number.
EX 36- 1×36, 2×18, so on and so on. Then do this for 27. The GCF will be the greatest factor. In this case, that is 9.
So there would be 9 groups because that is the greatest common factor.
there would be 4 roses in each group because 4×9= 36.
There are 3 carnations in each group because 9×3 =27.
So 9 groups with 4 roses and 3 carnations.
Figure
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Formula for the Conditional Probability is:
P ( A \ B ) = P ( A ∩ B ) / P ( B )
But it is not possible to have the probability greater than 1.
0 ≤ P ( n ) ≤ 1
So let`s assume that: P ( A ∩ B ) = 1320 and P ( B ) = 1325
P ( A \ B ) = 1320 / 1325 = 0.9962
Answer:
14/20 or .7 or 70%
Step-by-step explanation:
Total Number of cards: 20
Number of Red cards: 6
The leftover cards: 20 -6 = 14
The probability of not getting a red = 14/20
14/20 as a decimal = 14/20 = 70/100 = .7
14/20 as a percent = 14/20 = 70/100 = 70%
Flip the fraction to make the -3 exponet positive then it will be 9x^5/3x^3 which the answer would then be 3x^2