HELP ME PLEASE 100 POINTS

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

Answer:

#1) 4; #2) 12 inches; #3) (-0.8, 2.4); #4) (3.5, 8.75); #5) 32 inches by 64 inches

Explanation:

#1) To get the image points, each pre-image point was multiplied by 4. This means that the scale factor is 4.

#2) The perimeter of GAME is 177. We know that three of the sides are 35, 56 and 56. This means the fourth side, GA, would be

177-(35+56+56) = 177-147 = 30 inches

This means that GA to G'A' would have the same ratio as ME to M'E'; this gives us the proportion

$\frac{35}{14}=\frac{30}{x}$

Cross multiplying, we have

35(x) = 14(30)

35x = 420

Divide both sides by 35:

35x/35 = 420/35

x = 12

#3) To find the coordinates of I', we multiply the coordinates of I by the scale factor:

I' = (-2(2/5), 6(2/5)) = (-4/5, 12/5) = (-0.8, 2.4)

#4) To find the coordinates of S', multiply the coordinates of S by the scale factor:

S' = (2(7/4), 5(7/4)) = (14/4, 35/4) = (3.5, 8.75)

#5) The generic version is 3/8 the size of the brand name version. This means that the brand name version is 8/3 of the generic version. To find the dimensions of the brand name version, we multiply the dimensions of the generic version by 8/3:

12(8/3) = 96/3 = 32

24(8/3) = 192/3 = 64

The dimensions of the generic version are 32 by 64.

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A population of values has a normal distribution with μ = 149.8 μ=149.8 and σ = 68.2 σ=68.2. You intend to draw a random sample

Len [333]

Answer:

There is a 49.20% probability that a single randomly selected value is less than 148.3.

There is a 38.21% probability that a sample of size n = 186 n=186 is randomly selected with a mean less than 148.3.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A population of values has a normal distribution with $\mu = 149.8$ and $σ=68.2$ .