Answer:
Verify x+y+z)=(x+y)+z for the following values of x,y,z
(i)x=3/4,y=5/6,z=-7/8(
ii)x=2/; 3,y=-5/6,z=-7/9(
iii)x=3/5,y=-6/9,z=2/10(
iv)x=; - 3/5, y = - 7/10, z = - 8/15 To Verify x+(y+z)=(x+y)+z (i)x=3/4,y=5/6,z=-7/8 LHS = 3/4 + (5/6 + (-7/8)) = (3/4) + (5/6 -7/8)= (3/4) + ((20-21)/24) = 3/4 - 1/24 =(18-1)/24 = 17/24
RHS = (3/4 + 5/6) + (-7/8)= (9 + 10)/12 - 7/8 = 19/12-7/8 = (38-21)/24 = 17/24
LHS = RHS = 17/24 (ii) * x = 2/3, y = - 5/6, z = - 7/9 LHS = 2/3 + (-5/6+ (-7/9) = 2/3 + (-5/6 - 7/9) = 2/3 + (-29/18) = 2/3 - 29/18
= 12/18 - 29/18 = -17/18
RHS = (2/3 + (-5/6))+(-7/9) = (2/3 - 5/6) - 7/9 = (-1/6) - 7/9 = -1/6 - 7/9 = -3/18 - 14/18 =
-17/18
LHS = RHS....
Hence verified..
Step-by-step explanation:
hope it helps u no notebook
.???
It is not 7 it is 12. 3x4 = 12
Which question and if you have the name of the assignment or it has a copy right at the bottom you can most likely find it online hope that helps
Answer: 56 boxes
Step-by-step explanation: each box is worth 7.5 cubic feet, and if the space is 65% full, the remainder of space, being 420 cubic feet, can hold 56 boxes
