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Sergio039 [100]
2 years ago
5

Find the intersection of H and G find the union of H and G

Mathematics
1 answer:
ra1l [238]2 years ago
5 0

H∩G={1,9} INTERSECTION OF H AND G

H∪G={1,2,3,5,6,7,9,10,11,28} UNION OF H AND G

<u>Step-by-step explanation:</u>

Step-1:  

Let H={1,2,5,7,9,10} and G={1,3,6,9,11,28} are individual set

Intersection of H and G (H∩G) is {1,9} Which means the COMMON ELEMENTS in both the set.

Step-2:

Now the Union in both the set (H AND G) (H∪G) is {1,2,3,5,6,7,9,10,11,28}.

Which means ALL THE ELEMENTS in both set.

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Three fourths of 9.30
Marianna [84]
3/4 of 9.3

3 ÷ 4 = 0.75

0.75 × 9.30 = <span>6.975

therefore the answer is 6.975</span>
6 0
3 years ago
7g + 4g + 3g − 13g + g = 10 please help!!
Leona [35]
Combine like terms.


7g + 4g + 3g + g = 15g

15g - 13g = 2g


2g = 10


Divide by 2 on both sides.


g = 5
5 0
3 years ago
Read 2 more answers
Read below thanks :D
Ray Of Light [21]

Answer:

  (d)  112 m²

Step-by-step explanation:

The area of a parallelogram is given by the formla ...

  A = bh . . . . . . where b is the base length and h is the height

__

Here, the base is divided into parts, but their total length is 5m+9m = 14m. The height is given as 8m, so the area is ...

  A = (14 m)(8 m) = 112 m²

The area of the parallelogram is 112 square meters.

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<em>Alternate solution</em>

You can also figure this as the sum of the areas of the two triangles and that of the center rectangle.

  A = 2(1/2bh) +bh

  A = 2(1/2(5 m)(8 m)) +(9 m)(8 m) = 40 m² +72 m² = 112 m²

4 0
2 years ago
Given the arithmetic sequence an = 2 + 4(n − 1), what is the domain for n?
zlopas [31]
The answer should be A the first one
3 0
3 years ago
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Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
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