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3 years ago

PLEASE HELP ME WITH THIS MATH QUESTION PLEASE FILL ALL BLANKS

Mathematics

1 answer:

maxonik [38]3 years ago

3 0

Answer:

1/3
y-axis
(1, -2)

Step-by-step explanation:

The length AC is 3, but the corresponding length FD is 1, so the dilation factor is FD/AC = 1/3.

The reflection is a left/right reflection, so it is across a vertical line. We suspect the only vertical line you are interested in is the y-axis. (It could be reflected across x=1/2, and then the only translation would be downward.)

The above transformations will put C' at (1, 0). Since the corresponding point D is at (2, -2), we know it is C' is translated by (1, -2) to get to D.

C' + translation = D

(1, 0) +(1, -2) = (2, -2)

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Please help. Which number(s) below belong to the solution set of the inequality? Check all that apply. 9x > 117

lord [1]

Answer:

A, d and e

Step-by-step explanation:

So take the numbers a multiply them by nine. if they are more than 117, then they are correct, but with D 9x13 is equal to 117 so it is part of the solution set.

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3 years ago

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BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , <u>d</u> is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

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How many strings are there of four lowercase letters that have the letter x in them?

borishaifa [10]

We can subtract from the number of strings of length 4 of lower case letters the number of string of length 4 of lower case letters other than x. Thus the answer is 264 − 254 = 66,<span>351</span>

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4 years ago

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Answer:

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9514 1404 393

Answer:

Step-by-step explanation:

Given the triangle congruence statements, the segment and angle congruence statements must refer to corresponding vertices. Corresponding vertices are listed in the same order in the triangle congruence statement.

The one FALSE statement in the bunch is ...

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