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Virty [35]
3 years ago
14

Witch property of exponents must be used first to solve the expression (xy^2)1/3

Mathematics
1 answer:
vovangra [49]3 years ago
3 0

First you do the parenthesis

then you do the exponent in the parenthesis

Then the multiplication in the parenthesis

then when you are done multiplying in the parenthesis

then u multiply the answer in the parenthesis with 1/3

and then you are done

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Complete the pattern
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1.) 376.2
2.) 37620
3.)376200. 
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3 years ago
4. You purchase 3 items for $4.23. About how much did you spend?<br> $15<br> $12<br> $10<br> $13
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Answer:

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7 0
2 years ago
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A builder makes drainpipes that drop 1 cm over a
LUCKY_DIMON [66]

Answer:

700.4 cm

Step-by-step explanation:

This involves two similar triangles.

Both triangles are right triangles.

One has legs measuring 1 cm and 30 cm. We can find the hypotenuse by using the Pythagorean theorem.

(1 cm)^2 + (30 cm)^2 = c^2

c^2 = 901 cm^2

c = sqrt(901) cm

The second triangle has one leg with length 700 cm. This leg corresponds to the 30-cm leg in the other triangle. Since the triangles are similar, we can use a proportion to find the hypotenuse of the second triangle.

(30 cm)/(700 cm) = [sqrt(901) cm]/x

3/70 = sqrt(901) cm/x

3x = 70 * sqrt(901) cm

x = 70 * sqrt(901) cm/3

x = 700.4 cm

Answer: 700.4 cm

8 0
3 years ago
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Megan's text messaging plan costs $5 for the first 700 messages and 30¢ for each additional text message. If she owes $63.20 for
Setler [38]

Answer:

Fixed cost $14 -350 messages

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Step-by-step explanation:

3 0
2 years ago
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Help plzzzz! pre calc question
Mumz [18]

Answer:

\sum^{\infty}_0 {(-3)^n}

Step-by-step explanation:

Notice that the series: 1 - 3 + 9 - 27 +... clearly has powers of the factor 3 in its terms and it is also an alternate series (the terms alternate from positive to negative). The terms are positive for a_0, a_2, a_4, ... (even terms) , while the odd terms a_1, a_3, a_5, ... are negative. (so most likely there should be a factor   (-1) in the common ratio.

We can then represent it with the following summation expression:

\sum^{\infty}_0 {(-3)^n} given that each of its first four terms are:

a_0=(-3)^0=1\\a_1=(-3)^1=-3\\a_2=(-3)^2=(-3)*(-3)=9\\a_3=(-3)^3=(-3)*(-3)*(-3)=-27

7 0
3 years ago
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