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Yuki888 [10]
3 years ago
6

Plz help me answer this

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

sure

Step-by-step explanation:

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Select the postulate of equality or inequality that is illustrated.
Airida [17]
Hello,
"<" is transitive.
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b<2 ==>a<b<2==>a<2

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40 students where has their favorite shoe color <br> how many chose blue?
balandron [24]

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8 students

Step-by-step explanation:

There are 20 boxes and there are a total of 40 students interviewed. So, each box is worth 2 students. Since blue has 4 boxes, 4*2 = 8 students chose blue as their favorite shoe color.

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3 years ago
Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
vivado [14]

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

4 0
2 years ago
Cindy has printed 45 pages. Each page has 18 stickers
prisoha [69]

Answer:

810 stickers.

Step-by-step explanation:

Since there are 18 stickers per page, we need to use multiplication to calulate how many stickers we have total.

Our problem is 45*18, since we have 45 pages, each with 18 stickers.

45*18=810

Cindy has 810 stickers in all.

Hope this helps!

4 0
3 years ago
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