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SVEN [57.7K]
3 years ago
14

If each quadrilateral below is a rectangle find the missing measure in #5

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

Answer:

What do you mean by #5?

Step-by-step explanation:

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Consider a game in which you flip a coin. If it comes up heads, you earn 1 point; if it comes up tails, you earn 0 points. What
Sergeeva-Olga [200]

Answer:

C. 0.5

Step-by-step explanation:

Since a coin has 2 sides and there is the same probability of getting either side, then each side has a 50% or 0.5 probability. Therefore, in order to calculate the expected value of one coin flip we need to multiply the value of each side by its probability and add those values together like so...

1 * 0.5 = 0.5

0 * 0.5 = 0

Now we add these values together...

0.5 + 0 = 0.5

Finally, we can see that the expected value of one coin flip is 0.5

4 0
3 years ago
Write the set of all real numbers greater than 19 and less than 32 in set-builder notation.
Aleks04 [339]

Answer: {xI x ∈ R, 19 < x < 32}

Step-by-step explanation:

This notation is:

{xI condition1, condition2, ...}

The first condition is:

From what set we take the values of x?

From the set of real numbers.

x ∈ R

The other conditions are the limitations that we have for x, in this case:

19 < x < 32

Then we can write this as:

{xI x ∈ R, 19 < x < 32}

8 0
3 years ago
Solve each equation <br> -10=-14v+14v
Vinvika [58]

Answer:

No solution.

Step-by-step explanation:

Simplify. Combine like terms:

-10 = -14v + 14v

-10 = (-14v + 14v)

-10 = (0)

-10 ≠ 0 ∴ no solution is your answer.

~

3 0
3 years ago
What is the solution to 0.4(12 - 3x) = 0.3(12x - 16)?<br> F. 4<br> G. 2<br> H. -2<br> J. -4
jolli1 [7]
Answer : H-2
I can sure that's the answer
6 0
3 years ago
Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give
frutty [35]

Answer:

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

g(x) =e^{x^3}

  • we know that \frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)

g'(x) =e^{x^{3}}(3 x^{2})

g'(x) =3 x^{2} e^{x^{3}}

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}

using the equation of line:

(y-y_1)=m(x-x_1)

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\

y=\dfrac{3x}{e}+\dfrac{4}{e}

this is the equation of the tangent at point (-1,1/e)

3 0
3 years ago
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