The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.




Weights of at least 340.1 are in the highest 20%.
(a) Complementary angles
(b) Vertical angles
(c) Supplementary angles
<u>Explanation:</u>
Complementary angles are those two angles whose sum is 90 degrees.
Supplementary angles are those two angles whose sum is 180 degrees.
Vertical angles are the angles opposite each other when two lines cross.
(a)
Angles 1 and 5 are complementary angles
(b)
Angles 3 and 5 are vertical angles
(c)
Angles 3 and 4 are supplementary angles
For number 3, it is reciprocal
and for number 4, it is whole number
Answer:
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