Question

The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)

Answer 1

Answer:

y + 2 = $\frac{2}{3}$(x - 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = $\frac{2}{3}$(x - 3) ← is in point- slope form

with slope m = $\frac{2}{3}$

Parallel lines have equal slopes, thus equation of parallel line

with m = $\frac{2}{3}$ and (a, b) = Q(1, - 2) is

y - (- 2) = $\frac{2}{3}$(x - 1) , that is

y + 2 = $\frac{2}{3}$(x - 1)