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Tanya [424]
4 years ago
9

The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)

Mathematics
1 answer:
Musya8 [376]4 years ago
7 0

Answer:

y + 2 = \frac{2}{3}(x - 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = \frac{2}{3}(x - 3) ← is in point- slope form

with slope m = \frac{2}{3}

Parallel lines have equal slopes, thus equation of parallel line

with m = \frac{2}{3} and (a, b) = Q(1, - 2) is

y - (- 2) = \frac{2}{3}(x - 1) , that is

y + 2 = \frac{2}{3}(x - 1)

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To solve exponentials, we can take Natural Log (Ln) of both sides:

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