The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)
1 answer:
Answer:
y + 2 = (x - 1)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
y - 4 = (x - 3) ← is in point- slope form
with slope m =
Parallel lines have equal slopes, thus equation of parallel line
with m = and (a, b) = Q(1, - 2) is
y - (- 2) = (x - 1) , that is
y + 2 = (x - 1)
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In order to find the equation of a line, you would have to use the equation y=mx+b.
First, find the slope:
There is (1,8) and (2, 16) so plug that in 16-8/2-1 = 8. That's your slope! (Or the m)
Next in order to find b, you have to plug in a point:
y=8x+b
Take (1,8) and plug it in for x and y:
8=8(1)+b
b=0
Your y intercept is 0 (which you can also see on the graph)
So your answer is: y=8x
First, find the slope:
There is (1,8) and (2, 16) so plug that in 16-8/2-1 = 8. That's your slope! (Or the m)
Next in order to find b, you have to plug in a point:
y=8x+b
Take (1,8) and plug it in for x and y:
8=8(1)+b
b=0
Your y intercept is 0 (which you can also see on the graph)
So your answer is: y=8x