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Andrew [12]
3 years ago
7

Write the missing factor. (d-5)(?) = d^2-25

Mathematics
1 answer:
SOVA2 [1]3 years ago
6 0
d^2-25=d^2-5^2=(d-5)(d+5)\\\\Used:\ a^2-b^2=(a-b)(a+b)
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Question below answer correctly please
GREYUIT [131]

what equation am i suppose to be solving

5 0
3 years ago
Can somebody solve this?
erastova [34]

Answer:

∠ABC = 46°

Step-by-step explanation:

DB and BC are of same length (radius), making it an isosceles triangle.

The base of the triangle is the same at 23°, a total of 46°.

180° - 46° = 134°

But we need ∠ABC, and since points DBA lie on the circumference, it's a straight line.

Therefore, 180° - 134° = 46°

7 0
3 years ago
3/5, 1/2,5/7 as a common
miskamm [114]

a common what? denominator?


4 0
3 years ago
Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
What it 3 1/2 times 5
kirill [66]

17.5 that is your answer!

if you need anymore help message me in my inbox ;)


4 0
4 years ago
Read 2 more answers
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